The mass density of water vapor at 327.6 atm and 776.4 K is 133.2 kg/m³. Given that for water Tc = 647.4 K, Pc = 218.3 atm, a = 5.464 dm6 atm/mol2 b = 0.03049 dm³ /mol, and M= 18.02 g/mol, calculate (a) The molar volume. Then calculate the compression factor (b) from the data, (c) from the virial expansion of the van der Waals equation
The mass density of water vapor at 327.6 atm and 776.4 K is 133.2 kg/m³. Given that for water Tc = 647.4 K, Pc = 218.3 atm, a = 5.464 dm6 atm/mol2 b = 0.03049 dm³ /mol, and M= 18.02 g/mol, calculate (a) The molar volume. Then calculate the compression factor (b) from the data, (c) from the virial expansion of the van der Waals equation
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(Assume all gases are perfect unless stated otherwise. Unless otherwise stated, thermochemical data are for 298.15 K.)
Transcribed Image Text:The mass density of water vapor at 327.6 atm and 776.4 K is 133.2 kg/m³. Given that for
water Tc = 647.4 K, Pc = 218.3 atm, a = 5.464 dm6 atm/mol2 b = 0.03049 dm /mol, and
M= 18.02 g/mol, calculate
(a) The molar volume. Then calculate the compression factor (b) from the data, (c) from
the virial expansion of the van der Waals equation
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