Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Transcribed Image Text:The man pulls on the rope with a force of F = 20 N.
Determine the moment of this force about the base of
the pole at O. Solve the problem two ways, i.e., by using a
position vector from O to A, then O to B.
B
1.5 m
3 m
F
4 m
10.5 m
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- Calculate the moment about point O of the 200-lb force that lies in the X-Y plane shown below. Solve the force into rectangular components at point M. X(-)- Fy Y(+) Y(-) 2'-0" M F 3'-0" 30° F = 200 lb X(+)arrow_forwardFor the pipe and rope assembly shown in the the diagram, determine the magnitude of the projected component of the force F along the pipe AO and the moment of force F about Point O. a= 5.7marrow_forwardThe Force F acts at the end of the bracket as shown in the diagram. Calculate the moment of the force about point P. P 0.4 m 1 0.2 m 30° F = 400 Narrow_forward
- Don't copy and complete solution pleasearrow_forwardDetermine the moment about point B of each of the three forces acting on the beam using the Scalar Approach / Notation. F₁ = 375 lb 8 ft 6 ft 3 4 F₂ = 500 lb 5 ft- B 0.5 ft 30° F3 = 160 lbarrow_forwardDetermine the moment about point B of each of the three forces acting on the beam using the Scalar Approach / Notation. F₁ = 375 lb 8 ft 6 ft 3 4 F₂ = 500 lb 5 ft- B 0.5 ft 30° F3 = 160 lbarrow_forward
- Handle forces F1 and F2 are applied to the electric drill. Replace this force system by an equivalent resultant force and couple moment acting at point O. Express the results in Cartesian vector from. Determine the resultant force and the moment of the resultant forse about the point O. Express your answer in terms of the unit vectors i, j and k.arrow_forwardIf F = 300KN, determine the resultant couple moment. -2 m 2m F 30° 2 m 250 kNA 250 kN 2 m 30° 3. 2marrow_forwardReplace the effect of the forces, with the resultant Fv and the moment M at point D, if the force F1 acts at point A, A = (1,5; 1,5; 2) B= (1; 3,5; 1) F2 at point B and F3 at point C. C=(-1; 5,5; 0) D= (1; 1,5: - 0,5) F = (100; - 20; 0)N F, =(-40; -30; 15)N F, (0;-80; 120)N C YA F, ATA B.arrow_forward
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