1 The image presents a problem involving a beam with various loads applied to it. The diagram shows a horizontal beam supported at point A and connected by a cable to point B. The beam experiences five downward forces: \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \).These forces are evenly distributed, with distances between them as follows:- \( F_1 \) is located 6 inches from the left end of the beam.- \( F_2 \) is 8 inches to the right of \( F_1 \).- \( F_3 \) is 8 inches to the right of \( F_2 \).- \( F_4 \) is 6 inches to the right of \( F_3 \).- \( F_5 \) is 8 inches to the right of \( F_4 \).Point \( B \) is connected vertically by cable \( BC \), which passes over a pulley to point \( C \).Beneath the diagram, there are three fill-in-the-blank fields with dropdown menus to determine:1. The force in cable \( BC \) in pounds.2. The vertical reaction force at \( A \), with options to indicate direction (up, down, or N/A).3. The horizontal reaction force at \( A \), with similar direction options.This exercise is intended to teach how to calculate reaction forces and tension in static equilibrium scenarios involving distributed forces on beams. The loading for a beam is as shown in the figure, where \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \).Determine the reaction forces at \( A \) and the tension in cable \( BC \).- **Diagram Explanation:** - The beam is horizontal, with forces \( F_1 \) through \( F_5 \) acting vertically downward. - The distances between the forces are: 6 in. between \( F_1 \) and \( F_2 \), 8 in. between \( F_2 \) and \( F_3 \), 6 in. between \( F_3 \) and \( F_4 \), and 8 in. between \( F_4 \) and \( F_5 \). - Point \( A \) is a support, and Point \( B \) is connected to cable \( BC \), which runs to support \( C \).Input the following:- The force in cable \( BC \) is \(\_\_\_\_\_\_\_\_\) lbs tension.- The vertical reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\).- The horizontal reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\). - Options for direction: left, right, N/A.

F1 = 15 lbF2 = 12 lbF3 = 13 lbF4=16 lbF5 = 12 lbFrom free body diagramSummation of forces in x-direction is zero,ΣFx = 0Ax= 0 (Horizontal reaction force at A)Summation of forces in y-direction is zero,ΣFy = 0F1+ F2+ F3+ F4+ F5 - Ay + TBC = 015 + 12 + 13 + 16+ 12 - Ay + TBC = 0Ay - TBC = 68 lb. (1)Moment about B= 0ΣMB = 0F1 *(6+8+6+8) + F2 *(8+6+8) + F3 *(6+8) + F4 *8 - Ay *8 = 015*(6+8+6+8) + 12*(8+6+8) + 13*(6+8) + 16*8 - Ay*8 = 0Ay = 124.25 lb ( Vertical reaction force at A) Now from equation (1)Ay - TBC = 68TBC = 68 - 124.25 = - 56.25 lb Force in BC = 56.25 lb (Tension) Vertical reaction force at A = 124.25 lb (up) Horizontal reaction force at A = 0

Engineering

Mechanical Engineering

The loading for a beam is as shown in the figure, where F₁ = 15 lb, F2 =12 lb, F3 = 13 lb, F4 = 16 lb, and F5 = 12 lb. Determine the reaction forces at A and the tension in cable BC. F1 F2 F3 F4 Fs -6 in-8 in.6 in.--8 in- The force in cable BC is The vertical reaction force at A is The horizontal reaction force at A is B lbs tension. lbs (Click to select) (Click to select) up down N/A

The loading for a beam is as shown in the figure, where F₁ = 15 lb, F2 =12 lb, F3 = 13 lb, F4 = 16 lb, and F5 = 12 lb. Determine the reaction forces at A and the tension in cable BC. F1 F2 F3 F4 Fs -6 in-8 in.6 in.--8 in- The force in cable BC is The vertical reaction force at A is The horizontal reaction force at A is B lbs tension. lbs (Click to select) (Click to select) up down N/A

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Looking for the correct answer and an explanation.
ANSWER FAST
c) Sketch the stress distribution in the section X-X
Needs Complete and correct solution don't use chat gpt or ai i definitely upvote you. thank you.
At a certain instant, the particle of mass m has the position and velocity shown in the figure, and it is acted upon by the force F. Determine its angular momentum about point O and the time rate of change of this angular momentum. Use m = 2.8 kg, a = 0.58 m, b = 0.98 m, c = 0.60 m, and F = 100 N and v = 3.5 m/s. m F
2. Orientation is the general term used to describe the features. O linear O most important different angular relationship between
Determine the x, y, z components of reaction at the journal bearing C if 0 = 0°.
I need the answer in15 mints please please please best wishes Ahmed
For the beams below, determine the location of the maximum deflection using double integration method. For the beams below, determine the magnitude of the maximum deflection using double integration method. Use E = 200 x10^6 KPa and I = 1.440 x10^-5 m4
Select the true statement An automotive crank shaft is... O Is subjected to multiple fatigue load cycles Reduces in strength as a result of corrosion during normal engine operation Subjected to creep failure due to engine temperature Have a geometry manufactured by casting
B P. 200 mm 240 mm 60 30 KN Figure (1.15)
q1