The loading for a beam is as shown in the figure, where F₁ = 15 lb, F2 =12 lb, F3 = 13 lb, F4 = 16 lb, and F5 = 12 lb. Determine the reaction forces at A and the tension in cable BC. F1 F2 F3 F4 Fs -6 in-8 in.6 in.--8 in- The force in cable BC is The vertical reaction force at A is The horizontal reaction force at A is B lbs tension. lbs (Click to select) (Click to select) up down N/A

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The image presents a problem involving a beam with various loads applied to it. The diagram shows a horizontal beam supported at point A and connected by a cable to point B. The beam experiences five downward forces: \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \).

These forces are evenly distributed, with distances between them as follows:
- \( F_1 \) is located 6 inches from the left end of the beam.
- \( F_2 \) is 8 inches to the right of \( F_1 \).
- \( F_3 \) is 8 inches to the right of \( F_2 \).
- \( F_4 \) is 6 inches to the right of \( F_3 \).
- \( F_5 \) is 8 inches to the right of \( F_4 \).

Point \( B \) is connected vertically by cable \( BC \), which passes over a pulley to point \( C \).

Beneath the diagram, there are three fill-in-the-blank fields with dropdown menus to determine:
1. The force in cable \( BC \) in pounds.
2. The vertical reaction force at \( A \), with options to indicate direction (up, down, or N/A).
3. The horizontal reaction force at \( A \), with similar direction options.

This exercise is intended to teach how to calculate reaction forces and tension in static equilibrium scenarios involving distributed forces on beams.
Transcribed Image Text:The image presents a problem involving a beam with various loads applied to it. The diagram shows a horizontal beam supported at point A and connected by a cable to point B. The beam experiences five downward forces: \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \). These forces are evenly distributed, with distances between them as follows: - \( F_1 \) is located 6 inches from the left end of the beam. - \( F_2 \) is 8 inches to the right of \( F_1 \). - \( F_3 \) is 8 inches to the right of \( F_2 \). - \( F_4 \) is 6 inches to the right of \( F_3 \). - \( F_5 \) is 8 inches to the right of \( F_4 \). Point \( B \) is connected vertically by cable \( BC \), which passes over a pulley to point \( C \). Beneath the diagram, there are three fill-in-the-blank fields with dropdown menus to determine: 1. The force in cable \( BC \) in pounds. 2. The vertical reaction force at \( A \), with options to indicate direction (up, down, or N/A). 3. The horizontal reaction force at \( A \), with similar direction options. This exercise is intended to teach how to calculate reaction forces and tension in static equilibrium scenarios involving distributed forces on beams.
The loading for a beam is as shown in the figure, where \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \).

Determine the reaction forces at \( A \) and the tension in cable \( BC \).

- **Diagram Explanation:**
  - The beam is horizontal, with forces \( F_1 \) through \( F_5 \) acting vertically downward.
  - The distances between the forces are: 6 in. between \( F_1 \) and \( F_2 \), 8 in. between \( F_2 \) and \( F_3 \), 6 in. between \( F_3 \) and \( F_4 \), and 8 in. between \( F_4 \) and \( F_5 \).
  - Point \( A \) is a support, and Point \( B \) is connected to cable \( BC \), which runs to support \( C \).

Input the following:

- The force in cable \( BC \) is \(\_\_\_\_\_\_\_\_\) lbs tension.
- The vertical reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\).
- The horizontal reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\).
  - Options for direction: left, right, N/A.
Transcribed Image Text:The loading for a beam is as shown in the figure, where \( F_1 = 15 \, \text{lb} \), \( F_2 = 12 \, \text{lb} \), \( F_3 = 13 \, \text{lb} \), \( F_4 = 16 \, \text{lb} \), and \( F_5 = 12 \, \text{lb} \). Determine the reaction forces at \( A \) and the tension in cable \( BC \). - **Diagram Explanation:** - The beam is horizontal, with forces \( F_1 \) through \( F_5 \) acting vertically downward. - The distances between the forces are: 6 in. between \( F_1 \) and \( F_2 \), 8 in. between \( F_2 \) and \( F_3 \), 6 in. between \( F_3 \) and \( F_4 \), and 8 in. between \( F_4 \) and \( F_5 \). - Point \( A \) is a support, and Point \( B \) is connected to cable \( BC \), which runs to support \( C \). Input the following: - The force in cable \( BC \) is \(\_\_\_\_\_\_\_\_\) lbs tension. - The vertical reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\). - The horizontal reaction force at \( A \) is \(\_\_\_\_\_\_\_\_\) lbs \([ \text{click to select}]\). - Options for direction: left, right, N/A.
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