The load of point E is 0. Get the force of BD, CD, and CE

Determine the horizontal displacement of joint C.  The length, L, of trusses AC, BC is 1,300 mm. The applied force at joint C, is 5.0 kN. The cross-sectional area of both trusses, A, is 360 mm2. The elastic modulus of truss AC, E1, is 135 GPa. The elastic modulus of truss BC, E2, is 150 GPa.

A tapered bar AB of solid circular cross section and length L is supported at end B and subjected to a tensile load P at the free end A. The diameters of the bar at ends A and B are dA and de, respectively. Determine the elongation of the bar due to the load P, assuming that the angle of taper is small P da A B T dв 1 m

! Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A frame and loading are shown. B P D of c 120 mm 120 mm 120 mm 90 mm ↓ Determine the force acting on member ABC at B. Take P = 440 N. (You must provide an answer before moving on to the next part.) The force acting on member ABC at Bis N.

Please answer part C A = 150mm^2 E = 200GPa

The steel bars AC and BC, each of cross-sectional area 120 mm2, are joined at C with a pin. Determine the displacement of point C caused by the 15-kN load. Use E =200 GPa for steel.

The shaft is made from a solid steel section AB and a tubular portion made of steel and having a brass core. If it is fixed to a rigid support at A, and a torque of T = 50 lb.ft is applied to it at C, determine the rotation angle that occurs at C relative to A and compute the maximum shear stress and maximum shear strain in the brass and steel. Take Gst = 11500 ksi, Gbr = 5600 Ksi. 3 ft 2 ft 0.5 in. B 1 in. T = 50 lb·ft

A force F= 338 N is applied as shown to the bracket ABC. a=134 mm; b=54 mm; c=90 mm; B=33 in degree. F a IB b 4a) Determine the y component of the moment of the force F about point A in Nm.

Determine the reactions at the supports. Assume the support at A is fixed and that at B is a roller. Take E = 29x103 ksi. The Moment of inertia of each segment is shown in the figure. (By Using The Force Method) A 9 ft- IAB 30 k = 600 in 18 ft B 30 k IBC= 300 in | C 12 ft-

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