The line segment x = 1 - y, 0 ≤ y ≤ 1, is revolved about the y-axis to generate the cone in Figure 6.49. Find its lateral surface area (which excludes the base area). A (0, 1) x+y=1 B (1,0) FIGURE 6.49 Revolving line segment AB about the y-axis generates a cone whose lateral surface area we can now calculate O dx 2 ° S = 2x [^*^ √/ 1 + ( 1 ² ³ dy = 2x / ² (1 S X, 1+ dy 0 (1-y)√2y dy 1 dx 2 S = 2x [*^ √ 1 + = =+) ² dy = 2 = [" (1-3)√2dy S dy 0 dx S = 27 / ²x √/1 + (# ) ² dy = 27 / ² (1+ dy 0 dy=2л (1+y) √2dy O dx S=2x [ ^x√/1+ (#5) ³ dy=25 / ^ (1-y) √ydy dy 0 dx ° 2020 ["^ √/10 (2) 4-2 [ " (2-31 / 54 S = 2n x,/ 1+ dx=2r √ 2dx dy 0
The line segment x = 1 - y, 0 ≤ y ≤ 1, is revolved about the y-axis to generate the cone in Figure 6.49. Find its lateral surface area (which excludes the base area). A (0, 1) x+y=1 B (1,0) FIGURE 6.49 Revolving line segment AB about the y-axis generates a cone whose lateral surface area we can now calculate O dx 2 ° S = 2x [^*^ √/ 1 + ( 1 ² ³ dy = 2x / ² (1 S X, 1+ dy 0 (1-y)√2y dy 1 dx 2 S = 2x [*^ √ 1 + = =+) ² dy = 2 = [" (1-3)√2dy S dy 0 dx S = 27 / ²x √/1 + (# ) ² dy = 27 / ² (1+ dy 0 dy=2л (1+y) √2dy O dx S=2x [ ^x√/1+ (#5) ³ dy=25 / ^ (1-y) √ydy dy 0 dx ° 2020 ["^ √/10 (2) 4-2 [ " (2-31 / 54 S = 2n x,/ 1+ dx=2r √ 2dx dy 0
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter12: Angle Relationships And Transformations
Section: Chapter Questions
Problem 3CR
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![The line segment x = 1 - y, 0≤ y ≤ 1, is revolved about the y-axis to generate the
cone in Figure 6.49. Find its lateral surface area (which excludes the base area).
A (0, 1)
x + y = 1
B (1,0)
FIGURE 6.49 Revolving line segment AB
about the y-axis generates a cone whose
lateral surface area we can now calculate
O
dx 2
° S = 2x [^*^ √/ 1 + ( ² )³ dy = 27 / ² (1
S
X, 1+
dy
0
0
(1-y) √ 2y dy
1
dx 2
S = 2x [*^ √ 1 + = =+) ² dy=2= √ * (1-3) √/2dy
S
dy
dx
S = 27 / ²x √/1 + ( ) ³ dy = 27 / ² (1 +
dy
0
dy=2л (1+y) √2dy
O
dx
S=2x [ ^x√/1+ (# ) ³ dy=25 / ' (1-y)
dy
0
√ydy
dx
02-22 / "^ √/10 (2) 4-2 [ " (2-31 / 54
f'(1-y)
S = 2n x,/ 1+
dx = 2π
dy
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30fc4209-43ac-409b-8363-1a56de792bf2%2F4f92f855-fdec-4856-be68-febf2a442fdb%2Fhl322ag_processed.png&w=3840&q=75)
Transcribed Image Text:The line segment x = 1 - y, 0≤ y ≤ 1, is revolved about the y-axis to generate the
cone in Figure 6.49. Find its lateral surface area (which excludes the base area).
A (0, 1)
x + y = 1
B (1,0)
FIGURE 6.49 Revolving line segment AB
about the y-axis generates a cone whose
lateral surface area we can now calculate
O
dx 2
° S = 2x [^*^ √/ 1 + ( ² )³ dy = 27 / ² (1
S
X, 1+
dy
0
0
(1-y) √ 2y dy
1
dx 2
S = 2x [*^ √ 1 + = =+) ² dy=2= √ * (1-3) √/2dy
S
dy
dx
S = 27 / ²x √/1 + ( ) ³ dy = 27 / ² (1 +
dy
0
dy=2л (1+y) √2dy
O
dx
S=2x [ ^x√/1+ (# ) ³ dy=25 / ' (1-y)
dy
0
√ydy
dx
02-22 / "^ √/10 (2) 4-2 [ " (2-31 / 54
f'(1-y)
S = 2n x,/ 1+
dx = 2π
dy
0
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