The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 3%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability that a pregnancy will last 308 days or longer is (Round to four decimal places as needed.) b. Babies who are born on or before days are considered premature. (Round to the nearest integer as needed.)

A statistics professor gives a survey to each of the 100 students in an introductory statistics lecture. The survey asks the students how many text messages they think they sent yesterday. The data are included below. Use Excel to calculate the population standard deviation and the population variance. Round your answers to one decimal place. Do not round until you've calculated your final answer "Texts sent yesterday"61201664102313264109191657619321816148466162436641223687915924262531264199635316223464092146629424151993943696172733060372610590334274120216305567487494586257197618128101729108326212810453194623967379 Standard Deviation = Variance =

Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P80 Click to view page 1 of the table. Click to view page 2 of the table. The z-score that corresponds to P80 is (Round to two decimal places as needed.) Enter your answer in the answer box. of 1 at

You are given the following set of observations:  98, 77, 26, 33, 88, 90, 79, 81.  What would be the mean for this distribution?

Determine whether the following graph can represent a variable with a normal distribution. Explain your reasoning. If the graph appears to represent a normal​ distribution, estimate the mean and standard deviation.   Could the graph represent a variable with a normal​ distribution? Explain your reasoning. Select the correct choice below​ and, if​ necessary, fill in the answer boxes within your choice.A.​No, because the graph is skewed right.B.​No, because the graph is skewed left.C.​No, because the graph crosses the​ x-axis.D.​Yes, the graph fulfills the properties of the normal distribution. The mean is approximately enter your response here and the standard deviation is about enter your response here. ​(Type whole​ numbers.)

QUESTION 8 According to BusinessWeek, 44% of advertisers claim they have been a victim of internet click fraud. If 120 advertisers are survey more of them will claim they have been a victim of internet click fraud, a. None of the answers is correct Ob.0.8310 OC. 0.6293 d. 0.3707 e.0.1690 QUESTION 9 Assume the cost for an automobile repair is normally distributed with a mean of $524 and a standard deviation of $149. If the cost lower 7% of automobile repair charges, what is your cost? Click Save and Submit to save and submit. Click Save All Answers to save all answers. MacBook Air 20 F3 D00 F4 F2 F5 $ & 1 4 Q W R T Y #

Solve the problem.Assume that mountain lions' weights are normally distributed with a mean of 62.6 kilograms and a standard deviation of 2.6 kilograms. If 70 mountain lions are randomly selected, find the probability that they have a mean weight between 61.9 kilograms and 62.8 pounds.

M1

Please answer within 30min thanks.

Find the standard deviation, coefficient of variation, and the 88.9% Chebyshev interval. numbers- 14,45,54,59,46,50,29,12,19,36,38,40,43,41,10,50,41,25,19,39