The length of the secant RT times it’s external segment ST, equals the square of the tangent segment TU.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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The length of the secant RT times it’s external segment ST, equals the square of the tangent segment TU.
1. In the following figure, TV is tangent to the circle at point U. Use the figure
T
R
(a) Describe the relationship among the lengths of the segments forme
tangent segment, TU. You may use words and/or an equation.
(b) Suppose RT = 16 in. and ST = 4 in. Is it possible to find the length
length. If not, explain why not.
A. The length of the secant RT times its external segment, ST, equals
segment TU.
Mathematically it can be written as RT x ST = (TU)2
B. RT = 9 in, and ST = 4 in. It is possible to find the value length TU and
Intersecting Secant-Tangent Theorem as RT x ST (TU)2
(TU)2 = 9x4 = 36
TU = 36
So the length of TU = 6 inchesC
Transcribed Image Text:1. In the following figure, TV is tangent to the circle at point U. Use the figure T R (a) Describe the relationship among the lengths of the segments forme tangent segment, TU. You may use words and/or an equation. (b) Suppose RT = 16 in. and ST = 4 in. Is it possible to find the length length. If not, explain why not. A. The length of the secant RT times its external segment, ST, equals segment TU. Mathematically it can be written as RT x ST = (TU)2 B. RT = 9 in, and ST = 4 in. It is possible to find the value length TU and Intersecting Secant-Tangent Theorem as RT x ST (TU)2 (TU)2 = 9x4 = 36 TU = 36 So the length of TU = 6 inchesC
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