College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- If you and your friend are sitting on a seesaw and their masses are 60 kg and 80 kg, (a) how far you have to sit from the center of seesaw to balance it if your friend is sitting at 30 cm from the center on other side? (b) What are torques created by each of you? What are the directions of torque?arrow_forwardA force F=(-5j+3k)N is applied to an object that is a distance r=(2j+6k)m from a pivot point. (a) Calculate the torque on the object.(b) Calculate the angle between r and F.arrow_forwardTwo forces, F1=100 N (Newton) and F2=20N, are applied on opposite sides of a door's knob at angles theta_1=30 degrees and theta_2=60 degrees respectively, causing the door to rotate (about the axis passing though its hinges). If the distance from the knob to the rotation axis is 0.8 meter, find the net torque exerted on the door and specify the direction of rotation of the door (in this problem, assume that the force F1 causes a counterclockwise rotation and F2 a clockwise rotation). A.) Net Torque = 26.14 N.m; the door rotates counterclockwise. B.) Net Torque = -25.4 N.m; the door rotates counterclockwise. C.) Net Torque = 123.8 N.m; the door rotates clockwise. D.) Net Torque = 1.784 N.m; the door rotates clockwise.arrow_forward
- You stepped on the edge of a bicycle wheel (radius 0.622 m) to make it slow down. If you pressed with your foot with a force of magnitude 10.0 N directed towards the center of the wheel, and the coefficient of friction between the wheel and your shoe is 0.462, what is the magnitude of the torque due to the friction?arrow_forwardThe Achilles tendon inserts on the calcaneus (the heel bone) at a distance of 8 cm from the axis of the ankle joint. If the force generated by the muscles attached to the Achilles tendon is 3000 N, and the moment arm of this force about the ankle joint is 5 cm, what torque is created by these muscles about the ankle joint? Hopefully it’s enough torque to move out of the way so the arrow doesn’t shoot through the tendon.arrow_forwardAt the presentation ceremony, a championship bowler is presented a 1.58-kg trophy which he holds at arm's length, a distance of 0.655 m from his shoulder joint. (a) Determine the torque (in N · m) the trophy exerts about the shoulder joint when his arm is horizontal. (Enter the magnitude only.) (b) Determine the torque (in N · m) the trophy exerts about the shoulder joint when his arm is at an angle of 32.0° below the horizontal. (Enter the magnitude only.) N · marrow_forward
- A circular-shaped object of mass 9 kg has an inner radius of 7cm and an outer radius of 20 cm. Three forces (acting perpendicular to the axis of rotation) of magnitude 12 N,27 N, and 16 N act on the object as shown. The force of magnitude 27 N acts 29 0 below the horizontal. Find the magnitude of the net torque on the wheel about the center of the object. (HINT: DRAW THE r FROM THE CENTER OF THE WHEEL TO WHERE THE FORCE ACTS. THIS QUESTION IS TRYING TO TRICK YOU.) 12 N 29° 27 N 16 N Your answerarrow_forwardOn the basis of second condition of equilibrium. When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850m from the hinges. What torque are you exerting relative to the hinges?arrow_forwardWhen tightening a bolt, you push perpendicularly on a wrench with a force of 150 N at a distance of 0.125 m from the center of the bolt. Part (a) How much torque are you exerting on the wrench, in newton meters, relative to the center of the bolt? Part (b) What is this torque, in pound-foot?arrow_forward
- A simple pendulum consists of a small object of mass 3.5 kg hanging at the end of a 2.0-m-long light string that is connected to a pivot point. (a) Calculate the magnitude of the torque (due to the force of gravity) about this pivot point when the string makes a 7.0° angle with the vertical. (b) Does the torque increase or decrease as the angle increase?arrow_forwardForce F = (-7.0 N)î + (5.0 N) ĵ acts on a particle with position vector7 = (4.0 m)î + (5.0 m) ĵ. (a) What is the torque on the particle about the origin, in unit-vector notation? = N: m (b) What is the angle between the directions of r and Torque is the cross product of a position vector (extending from a chosen point, here the origin, to the particle) and a force vector. Did you take the cross product in unit-vector notation? Do you remember how find the angle between two vectors by taking a dot product in both unit-vector notation and also in magnitude-angle notation? (You can similarly use a cross product to do this.) Do you remember how to find the magnitude of a vector from its components?arrow_forwardTo develop muscle tone, a woman lifts a 2.00-kg weight held in her hand. She uses her biceps muscle to flex the lower arm through an angle of 60.0°. (a) What is the angular acceleration if the weight is 24.0 cm from the elbow joint, her forearm has a moment of inertia of 0.250 kg and the net force she exerts is 750 N at an effective perpendicular lever arm of 2.00 cm? (b) How much work does she do? m²arrow_forward
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