The laminated beam, shown in cross section, is composed of ?ve 6- in. by 2-in. planks that are glued together. The beam carries a uniformly distributed load of intensity we over its 8-ft simply supported span. glue, 90 psi for shear in wood, and 800 psi for bending in wood, If the working stresses are 75 psi for shear in 6 in. 1. determine the maximum allowable value of we so that the shear stress in the wood is not exceeded. А. 900 lb/ft В. 555 lb/ft с. 833 lb/ft D. NOTA determine the maximum allowable value of we so that the shear stress in the glue is not exceeded. 900 lb/ft 2. А. В. 555 lb/ft С. 833 lb/ft D. NOTA 3. determine the maximum allowable value of we so that the bending - 5 @ 2 in. = 10 in.

Derive the maximum steel ratio and the recommended rteel ratio fe' O.856 fy Po-004 3 0.85 fc' pooos= 0-85

(2) 4 0 5 211 5 4 #9 4 "1 16 #3" ft-k fé = 3 ksi, M = 90 NWC. The section is cracked. Computer the bending stresses in the beam by using transformed-area metho

Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in