The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34

The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.7P

See similar textbooks

Related questions

Q: A Standard Proctor compaction test performed on a sample of crushed limestone (G; = 15.70) obtained…

Q: A sand cone equipment is used to perform a field density test on a compacted earthfill. Weight of…

Q: FALLING HEAD PERMEABILITY TEST OTHER QUESTIONS: 1. What is the importance of finding the coefficient…

A: Step: 1 “Since you have posted multiple sub-parts, we will solve first three sub-parts for you. To…

Q: 10. The results of a Standard Proctoretest is tabulated as follows: (SEE PICTURE) Determine the…

Q: The laboratory compaction test has a max. dry unit weight of 19kN/m³ with an optimum moisture…

Q: A clayey sand (SC) was compacted into a 1/30th cubic foot cylindrical Proctor steel mold with the…

A: Given:Volume of the mold (V) = 1/30 ft3 Weight of dry soil (Wd) = 4.18 lbWeight of wet soil (W) =…

Q: A stander protector test was performed on a sample of sandy silt soil: the test are shown below:…

Q: Problem 1) A soil sample was compacted. The result of the standard proctor test shows that at 100%…

Q: Draw the compaction curve using the following given data from a standard Proctor test. 2. From…

A: Objective: To draw the compaction curve for the given Standard Proctor Test results, and determine…

Q: Following are the results of a field unit weight determination test on the same soil with the sand…

A: Soil compaction is a process in which the soil retains mechanical pressure and is compacted. The…

Q: From a compaction test the dry density of soil was found to be 1860kg/m3. when the water content was…

A: Given Data: Dry density of soil, ρd=1860 kg/m3Water content, w=15% =0.15Diameter of the cylinder…

Q: The result of falling head permeability test for clay sample having an area of 1500 mm² and a length…

Q: Problem 1: The table below present the results of a standard proctor test of a borrow pit soil. FEB…

Q: A saturated 100 cm³ clay sample has a natural water content of 30%. It is found that the shrinkage…

Q: The following are the data of the compaction test: Volume of mold = 0.000945 m^3 Determine the…

A: Calculation of water content water content=wwws

Q: A sand cone test has been performed in a recently compacted fill. The test results obtained are as…

A: Relative compaction is 95.23%Explanation:

Q: Compute compaction of the tested soil if the laboratory moisture-density curve indicates a dry…

A: This question is from Geo technical engineering

Q: For a given soil (Gs = 2.72), following are the results of compaction tests conducted in the…

Q: 1. Sand cone equipment is used to determine an in-place unit weight (field density test) on a…

Q: The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc…

Q: An undisturbed soil sample 30 mm thick got 50% consolidated in 20 minutes with drainage allowed at…

A: Given, Consolidation test result of laboratory, t1= 20min H1= 30mm For field:- H2= 4m Find:- time…

Q: The field unit weight of the soil is 1960 kg/m3 and the unit weight of the soil particle is 2700…

A: Given data in question Bulk unit weight Unit weight of solids Maximum void ratio Minimum void…

Q: The results of a field unit weight determination test performed by means of the sand cone method are…

A: Given Calibrated dry unit weight of Ottawa sand, Yd1 = 104 pcf Weight of Ottawa sand to fill the…

Q: A sample of field soi! is tested in the laboratory. The results of Standard Proctor test at optimum…

A: Degree of compaction Soil compaction is the process of applying mechanical compaction effort to the…

Q: A standard compaction test was carried out in a mould of volume 0.001 m³1. Test results ar tabulated…

A: V = 0.001 m3Gs = 2.67

Q: The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc'…

A: Given:- The laboratory compaction test of a certain type of soil gives a maximum dry density of…

Q: 2. The coefficient of permeability for a fine-grained soil is determined in the laboratory by use of…

A: ANSWER:- Falling head Permeability test is used for fine grained soil as constant head Permeability…

Q: A 1 m thick soil with an initial void ratio of 0.94 was compacted by a roller and its thickness…

A: Given Layer thickness = H = 1 me0 = 0.94 .... initial void ratio∆H = 0.09 m .... reduced change in…

Q: Q1. Grain-size distribution of a soil obtained using sieve shaking and hydrometer test gave the…

Q: A Standard Proctor compaction test performed on a sample of crushed limestone (G; = 9.70) obtained a…

Q: b. For the results obtain in QB1(a) determine the void ratio - e and porosity - n for the soil at…

A: As per the guidelines of Bartleby We are only supposed to answer first three sub parts of a…

Q: compaction test of a certain type of soil

A: Field unit weight of soil is = weight / volume. Volume = 0.001337 cubic meter = 1337 cubic…

Q: plume of Proctor Mold (cm³) Moisture Content (w% mold (kg) 943.3 1.65 5.5 943.3 1.70 7.3 943.3 1.80…

A: Yd = dry unit weight w = moisture content Yb = wet unit weight / bulk density

Q: An undisturbed sample of soil obtained from field weighed 18 N with a volume of 10-3 m3. The dry…

Concept explainers

Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc³ with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method.

Volume of soil excavated from the hole = 0.001337 m³

Weight of moist soil from the hole = 2220 g

Weight of oven dried soil = 1890 g

Select one:

a. 97.25

b. 95.10

c. 90.34

d. 88.41

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the field unit weight of the soil in g/cc3 using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1486 g/m3 with an optimum moisture content of 12.5%. The following are the results of a field unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of soil from the hole when wet = 2220 g Weight of soil from the hole when dried = 1890 g Determine the field unit weight of soil in g/cm3. Determine the relative compaction, then tell whether it is within the allowable range for relative compaction of 95 ± 0.20?
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc' with an optimum moisture content of 12.5%. Determine the field unit weight of the soil in g/cc using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m³ Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 1.66 b. 1.58 C. 1.92 d. 1.87 It is the ratio of the volume of water to the volume of voids. Select one: a. Degree of saturation O b. Porosity c. Density d. Void ratio
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cm3 with an optimum moisture content of 12.5%. The following are the results of a field unit weight determination test using sand cone method. Volume of the soil excavated from the hole = 0.001337 m3 Weight of soil from the hole when wet = 2220 g Weight of soil when dry = 1890 g What is the in situ water content of the soil? O 17.46% O 19.21% O 15.55% O 14.12%
1. Sand cone equipment is used to determine an in-place unit weight (field density test) on a compacted earth fill. Ottowa sand is used in the cone and is known to have a bulk density of 100 pcf. a. From the information given below, determine the in-place dry unit weight of the tested soil, and the water content. Soil sample dug from test hole wet weight = 4.62 lb Dried Weight of soil sample = 4.02 lb Weight of Ottowa Sand (Sand Cone) to fill test hole = 3.60 lb b. Determine the percentage of compaction of the tested soil if the laboratory moisture unit weight curve indicates a dry unit weight of 115 pcf and optimum moisture content of 13 percent.
An in-place density determination (in-place unit weight) is made for the sand in a borrow pit using a balloon-type density apparatus. The damp sample dug from a test hole is found to weigh 37.90 N. The volume of the test hole is 0.00184m2. A. Compute the wet unit weight. B. This soil is to have a water content of 15%. Compute the dry unit weight of the soil. C. Compute the specific gravity of the soil if it has a void ratio of 0.423
Sand cone equipment is used to perform a field density test on a compacted earth fill. • Soil sample dug from the test hole = 20.60 N • Dry weight of soil sample = 17.92 N Ottawa sand used to fill the hole weighs 16.05 N and is known to have a density of 15.74 kN/m3. Determine the in-place dry density of the tested soil. Answer:
A sample of soil compacted according to the standard Proct or test has a density of 2.06 g/cm³ at 100% compaction and at an optimum water content of 14%. What is the dry unit weight? What is the dry unit weight at zero air-voids? If the voids become filled with water what would be the saturated unit weight? Assume Gs = 2.67 Air Water Solids Ma + - + M st
The results from a soil compaction test are shown in the table below. The solid grains of the soil have a specific gravity of 2.65. Yary (kN m³) at 2.5% air voids Sample W. m/c(%) (KN/m') Yary (kN/m) 19 12 20.9 3. 16 20.2 4 20 19.7 Which series below gives the dry density at 2.5% air voids (samples 1 to 4) in above table: a. 20.5, 19.2, 17.8, 16.6 O b. 20.2, 19.2, 17.8, 17.0 O. 20.5, 19.2, 17.8, 17.0 O d. 20.5, 19.2, 18.1, 16.6
10. The results of a Standard Proctoretest is tabulated as follows: (SEE PICTURE) Determine the maximum dry unit weight of compaction Determine the optimum moisture content Determine the void ratio at the optimum moisture content Gs = 2.70 Determine the degree of saturation at the optimum moisture content A field unit determination test for the soil, yielded the following data. Moisture content = 12% and moist unit weight = 106 pcf. Determine the relative compaction.
Laboratory compaction test results on a clayey soil are listed in the table below. Moisture content (%) Dry unit weight (kN/m³) 6 14.80 8 17.45 9 18.52 11 18.9 12 18.5 14 16.9 The following are the results of a field unit weight determination test on the same soil with the sand cone method: Calibrated dry density of Ottawa sand = 1,560 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.565 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil from hole = 2.85 kg Moisture content of moist soil = 15.2% Determine: a. Dry unit weight of compaction in the field. (Enter your answer to three significant figures.) Ya = ]kN/m³ b. Relative compaction in the field. (Enter your answer to two significant figures.) R = |%
Please answer the following questions. In solving the problems, you should use stored values to get the exact values.