
Chemistry
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ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:Question 24 of 25
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The Kp for the reaction A (g) =2 B
(g) is 0.0450. What is Kp for the
reaction 2 A (g) =4 B (g)?
1
2
3
C
7
9.
+/-
x 10 0
LO
00
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- The value of Kp for the reaction 2 A(g) + B(g) + 3 C(g) → 2 D(g) + E(g) is 16870 at a particular temperature. What does the magnitude of Kp tell us about the equilibrium position of the reaction? A) There are many more products than reactants. B) There are only a few more products than reactants. C) There are many more reactants than products. D) There are only a few more reactants than products.arrow_forwardN204(g) = 2 NO2(g) Three experiments were run starting with different initial amounts of N2O4(g) ([N204]o in the table). The systems were allowed to reach equilibrium and the concentrations for each gas were measured (in units of moles/Liter). For each of the boxes below, calculate the ratios indicated by the column heading. This will show the mathematical relationship that exists between the concentrations of NO2 and N204 at equilibrium. Be sure to round to the correct number of significant figures. Exp[N204l0 [NO2][N,04] [NO,] / [N204] 2 [NO,] / [N204] [NO2]? / [N204] 1 3.7 2.92 2.2 2 3.0 2.56 1.7 3 2.3 2.15 1.2 Based on your calculations, indicate whether each statement is True (T) or False (F): v1. Each experiment started with a different initial concentration of N204. v2. The ratio ([NO2] / [N204]) is equal to a constant value. v3. The ratio (2 [NO2] / [N204]) is equal to a constant value. v 4. The ratio ([NO2]? / [N204]) is equal to a constant value. v5. Each experiment reached a…arrow_forwardFor a particular reaction at 298 К., Кр 3.445 x 10^-3. When the same reaction is re-run at a lower temperature (155 K), Kp = 1.690 x 10^-5. The reaction is ................ a)endothermic exothermic atequilibrium complete .arrow_forward
- An empty steel container is filled with 0.0490 atm of HF. The system is allowed to reach equilibrium. If Kp = 2.76 for the reaction below, what is the equilibrium partial pressure of H₂? 2 2 HF (g) → H2 (g) + F2 (g)arrow_forwardThe value of Kp for the reaction 2 A(g) + B(g) + 3 C(g) → 2 D(g) + E(g) is 12770 at a particular temperature. What does the magnitude of Kp tell us about the equilibrium position of the reaction? A) There are many more products than reactants. B) There are only a few more products than reactants. C) There are many more reactants than products. D) There are only a few more reactants than products.arrow_forwardAt 1560 oC the equilibrium constant for the reaction: 2 IBr(g) I2(g) + Br2(g) is KP = 0.846. If the initial pressure of IBr is 0.00674 atm, what are the equilibrium partial pressures of IBr, I2, and Br2?p(IBr) = p(I2) = p(Br2) =arrow_forward
- What is the difference between KD and KA? in relation to “Law of Mass Action"arrow_forwardGiven the following equilibrium constants at 700K, 2 N2O(g) (double arrow) 2 N2 (g) + O2(g) K1 = 8.2 x 1033NO2(g) (double arrow) 1⁄2 N2(g) + O2(g) K2 = 2.44 x 108N2O4(g) (double arrow) 2 NO2(g) K3 = 4.6 x 10-3 determine the values of the equilibrium constants for the following reaction. Show your equation-buildingprocess and your calculations. 2 N2O4(g) (double arrow) 2 N2O(g) + 3 O2(g) K =arrow_forwardConstruct the expression for Kp for the following reaction. C(s) + 2 H₂(g) CH4(g)arrow_forward
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