The kinetic energy of a moving body is given by K = 2v², K being in joules and v in m/s. Its momentum when traveling with a velocity of 2 ms¹ will be:

The muon is an unstable subatomic particle witha mean lifetime of 2.2 μs, and about 10,000 muons reach everysquare meter of the earth's surface a minute. A muon has a linear momentum G, and after some short time it decays into two other elementary particles with masses m1 and m2. The energy Q released during the decay is converted entirely into the kinetic energy of the decay products (i.e., into kinetic energy of m1 and m2). Find linear momenta of decay products. Draw a vector diagram showing a range of momenta decay products can take.

A proton and anti-proton with rest energy of, E0 - 931 MEV/C“ was traveling in opposite direction at a speed of, V = 0.9995*C (where C is a speed of light equal to 3.0 * 108 m/s). After travelling in a vacuum chamber, the two particles collide head on to produce a new massive particle in the center of the chamber What is the new kinetic energy the proton and anti-proton in Giga electron Volt, after reaching the new speed? OK

dx 4x 3. In so-called "natural units" (which is just a sneaky way to let us ignore a bunch of constants), the relativistic kinetic energy of a rigid body is given by the formula 1 КЕ — т V1 – v2 where m is the rest mass of the body and v is its relative speed. Alien scientists on a space station are observing an object falling into a black hole. As the object falls, it is disintegrating, losing mass at a rate of 3 (so its mass is changing at a rate of -3). How fast is the kinetic energy of the main part of the object changing when its mass is 20, its velocity is .7, and it is accelerating at a rate of .1 (remember that acceleration is the derivative of velocity with respect to time: a = dt 1Note that this formula does not make sense when v > 1. That is because in natural units, a speed of 1 corresponds to the speed of light, and nothing with positive rest mass can go that fast.