The intermediates A, B, C, D, E, and F all occur in the same biochemical pathway G is the product of the pathway, and mutations 1 through 7 are all G –, meaning that they cannot produce substance G. The following table shows which intermediates will promote growth in each of the mutants. Arrange the intermediates in order of their occurrence in the pathway at which each mutant strain is blocked. A “+” in the table indicates that the strain will grow if given that substance, an “o” means lack of growth.

You generate mutants in the metabolic pathway for starlase. You conduct some complementation tests (after testing for dominance of course) and come up with the following results: 1 2 4 6 1 + + + 2 + 3 + 4 + 5 6 a. How many complementation groups are there? [Select] b. You conduct some additional experiments to elucidate the starlase metabolic pathway. Your results are shown below. Use this information alongside information from the complementation table above to place the intermediates in the correct order on the pathway. (HINT: use the complementation groups from the table above to help you consolidate information on the tables below. Reference practice question 3 from today's lecture for help). Addition to minimal medium Mutant None starlase P 1 + + 2 + + 4 + + 5 + 6 Precursor --> [ Select ] [ Select ] [ Select ] --> starlase c. Mutant 4 has a loss-of-function mutation for which enzyme in the starlase synthesis pathway? [ Select ] E1 E2 ЕЗ Е4 Precursor > Intermediate 1→ Intermediate…

For the following genotypes of E. coli strains, state whetherenzyme activity is inducible (I), constitutive (C), or uninducible (U).Key to symbols in table:z = structural gene for  -galactosidasey = structural gene for permeasea = structural gene for transacetylasep = promoter (for lac operon)i = structural gene for the lac repressor (regulator gene)o = operator (binding site for repressor)Genotype                                 -gal (z)                       Permease (y)                         Transacetylase (a)i+ p+ oC z- y- a+i- p+ o+ z+ y- a- /i+ p- oc z- y+ a-i- p+ o+ z+ y- a+ /i+ p+ oc z- y+ a-i+ p+ o+ z- y- a+i- p- o+ z+ y- a+ /i- p+ o+ z- y+ a-iS p+ o+ z- y- a+i- p+ o+ z+ y- a+ /i+ p- oc z- y+ a-is p+ o+ z- y+ a+ /i+ p+ oc z+ y- a-i- p- o+ z+ y- a+ /i- p+ o+ z- y- a-is p+ oc z+ y- a+i+ p+ oc z+ y- a+

What is the correct answer, and why?