Please answer the questions with steps and correct answer 5The integral ₁|102² – 2³ – 24z| da MUST be evaluated by breaking it up into a sum of three integrals:-wherea =C =a₁10x² - x³ - 24x| dx =X10x² - 2³ - 24x| dx =5[° | 10x² – x³ – 24x| dx =5> | ₁ |10x² – 2³ – 24a| dr = [0Thus₁|102² - 2³ - 24x|dx+√|102² – 2³ – 24x| dæ+a5[³|102² – 2³ – 24x| da-

The given integral is:∫-15 10x2-x3-24x dx

The integral ₁ |102² – 2³ – 24x| da MUST be evaluated by breaking it up into a sum of three integrals: ₁|102² – 2³ – 24x| da+ S|102² – x³ – 24x| dz+ where a = C= a ₁10x² - 2³ - 24x| dx = [₁|10x² – 2³ – 24x| dx = √³|10x² – x³ – 24x| dx = ³ [₁|102² – 2³ – 24z| dx = [0 Thus 5 √³|102² – 2³ – 24x| da

The integral ₁ |102² – 2³ – 24x| da MUST be evaluated by breaking it up into a sum of three integrals: ₁|102² – 2³ – 24x| da+ S|102² – x³ – 24x| dz+ where a = C= a ₁10x² - 2³ - 24x| dx = [₁|10x² – 2³ – 24x| dx = √³|10x² – x³ – 24x| dx = ³ [₁|102² – 2³ – 24z| dx = [0 Thus 5 √³|102² – 2³ – 24x| da

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.4: Definition Of Function

Problem 52E

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