The input/output table below defines a function f(x, y, z). Create and fill in a new column for f(x, y, z). Then find a DNF expression equivalent to f(x, y, z). xyz f(x, y, z) 000 0 001 0 1 0 0 1 1 100 1 0 1 1 10 S 11 1 1 0 1 0 1 0 2.With CamScanner

Define a function calc_total_inches, with parameters num_feet and num_inches, that returns the total number of inches. Note: There are 12 inches in a foot.Sample output with inputs: 5 8 Total inches: 68

Using Python

Complete the function that calculates the sum of the first n+1 terms of the geometric series a, ar, ar² ar³, ar4 . note that the series begins with a and the last term is ar", in total there are n+1 terms. ar" ... [ ]: # complete the function given the variables a,r,n and return the value as series_sum. def sum_geometric_series(a,r,n): # your code here return series_sum

The Mux below implements the function F = 8 to 1 MUX ABC F Select one: O a. F = A'B'C + AB'C + ABC O b. F = A'B'C' + AB'C + AB'C + ABC' OC F=A'B'C' + A'BC' + A'BC + AB'C' + AB'C' O d. F= A'B'C + A'BC' + A'BC + ABC

please answer in matlab

Using the celsius_to_kelvin function as a guide, create a new function, change the name to kelvin_to_celsius, and modify the function accordingly.Sample output with input: 283.1510.0 C is 283.15 K 283.15 K is 10.0 C   def celsius_to_kelvin(value_celsius):    value_kelvin = 0.0     value_kelvin = value_celsius + 273.15    return value_kelvin INSERT CODE  value_c = 10.0print(value_c, 'C is', celsius_to_kelvin(value_c), 'K') value_k = float(input())print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')

Please answer in matlab code.

Using python in jupyterlab

Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C Learn how our autograder works 461710 3116374.qx3zqy7 1 def celsius_to_kelvin (value_celsius): value_kelvin = 0.0 12345 3 4 6 7 Your solution goes here """ 8 9 value_c= 10.0 10 print(f' {value_c} C is {celsius_to_kelvin(value_c)} K') 11 value_kelvin value_celsius + 273.15 return value_kelvin 111 Run 12 value_k = float(input()) 13 print(f' {value_k} K is {kelvin_to_celsius(value_k)} C')