Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- The equilibrium constant for the reaction 2NO(g) + Br₂ (g) = 2NOBr(g) is Ke = 1.2 x 10-2 at a certain temperature. ▶ Part A Part B Calculate Ke for the following reaction: Express your answer to two significant figures. Kc = Submit 15 ΑΣΦ Request Answer ? 2NOBr(g) = 2NO(g) + Br₂(g)arrow_forwardIn air at 25 °C and 1.00 atm, the N₂ concentration is 0.01 M and the O₂ concentration is 0.033 M. The reaction N₂(g) + O₂(g) → 2NO(g) has Kc = 4.8 x 10-³1 at 25 °C. Taking the N₂ and O₂ concentrations given above as initial values, calculate the equilibrium NO concentration that should exist in our atmosphere from this reaction at 38 °C, Kc = 1.0E-29. Make simplifying assumptions in your calculations. (Express your answer in scientific notation.) [NO] = i Marrow_forwardA student ran the following reaction in the laboratory at 431 K: PC15 (9) PC13 (g) + Cl₂ (g) When she introduced 2.98 moles of PC15 (g) into a 1.00 liter container, she found the equilibrium concentration of PC15 (9) to be 2.94 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = Submit Answer [Review Topics] [References] Use the References to access important values if needed for this question. Show Hint Retry Entire Group 9 more group attempts remaining 2 Previous Next or n er etarrow_forward
- The equilibrium constant, Kc, for the following reaction is 2.0. If the equilibrium mixture contains 1.8 M NO and 0.70 M Br2, what is the molar concentration of NOBr? 2NOB1(g) = 2NO(g) +Br2 (g) Express your answer to two significant figures and include the appropriate units.arrow_forwardInitial (M) Change (M) Equilibrium (M) Consider the reaction of SO₂ and O₂ described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 SO₂(g) + O₂(g) = 2 SO₂(g) NEXT A 2.00 L reaction vessel was filled 0.0432 mol SO₂ and 0.0296 mol O₂ at 900 K and allowed to react. At equilibrium, the concentration of SO, was found to be 0.0175 M. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. -0.00875 0.0209 0 0.00875 2SO₂(g) Question 20 of 33 2.00 0.0216 0.0432 0.0148 0.0296 0.0041 O₂(g) 0.0175 2 0.0129 -0.0175 0.0061 RESET -0.0350 0.0257 2SO₂(g)arrow_forwardHydrogen and chlorine react to form hydrogen chloride, like this: H,(g) + Cl,(g) 2 HCl(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, chlorine, and hydrogen chloride has the following composition: compound concentration at equilibrium 0.86 M Cl, 0.30 M HC1 1.9 M Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K = 0arrow_forward
- Calculate the equilibrium concentrations of H2, I2, and HI at 700 K if the initial concentrations are [H2] = 0.110 M and [12] = 0.270 M. The equilibrium constant Kc for the reaction H2(g) +I2(g) = 2 HI(g) is 57.0 at 700 K. Part A Calculate the equilibrium concentrations of H2. Express your answer to three decimal places and include the appropriate units.arrow_forwardConsider the hypothetical reaction A(g) 2B(g). A flask is charged with 0.74 atm of pure A. after which it is allowed to reach equilibrium at 0 °C. At equilibrium the partial pressure of A is 0.37 atm Part A What is the total pressure in the flask at equilibrium? Express your answer using two significant figures. VS ΑΣΦ 4 P₁ = Submit Part B What is the value of Kp? Express your answer using two significant figures. K₂= Submit Part C Request Answer |VL ΑΣΦ Submit Request Answer What could we do to maximize the yield of B? → Request Answer [w] ? O Doing the reaction in a larger flask maximizes the yield of B. O Doing the reaction in a smaller flask maximizes the yield of B. atmarrow_forward3 A + 2B 1 C Calculate the equilibrium constant (K) for the following reaction at 1000. K, using this information: A and B are placed in a flask and at the beginning of the reaction [A] is 6.87 M and [B] is 6.38 M. After the reaction has reached equilibrium, [C] is 1.47 M. Unfortunately, significant figures cannot be taken into account here, so please ignore them this time. 119.84085 0.00132 0.00011 0.03354 0.00834 1 1 1arrow_forward
- Consider the quilibrium reaction between X and Y, as shown below: X=Y AG The reaction is started with 10 mmol of X; no Y is initially present. After 48 hours, analysis reveals the presence of 10 mmol of X and 0 mmol of Y. Which is the most likely explanation? = −1 - 45 kJ mol X and Y have reached equilibrium concentrations. An enzyme has shifted the equilibrium toward X. Formation of Y is kinetically slow; equilibrium has not been reached by 48 hours. Formation of Y is thermodynamically unfavorable. Two of the above explanations are reasonable.arrow_forwardFor the reaction 12(g) +Br₂(g) →21Br(g) Ke=280 at 150 °C. Suppose that 0.520 mol IBr in a 2.00-L flask is allowed to reach equilibrium at 150 °C. Esc Type here to search WE in R ▼ What is the equilibrium concentration of I₂? Express your answer in moles per liter to three signifi IVE ΑΣΦ [12] = 0.012 Submit Previous Answers Request Answer * Incorrect; Try Again; 7 attempts remaining Part C What is the equilibrium concentration of Br₂? Express your answer in moles per liter to three significant figu ΕΧΕΙ ΑΣΦ Br₂ = 0.0120 Submit Previous Answers Request Answer ? 8 Marrow_forwardConsider the reaction 2 NH3 (g) ⇄ N2 (g) + 3 H2 (g). Suppose 6 moles of pure ammonia are placed in a 1.0 liter flask and allowed to reach equilibrium. If X represents the concentration (in M) of nitrogen present in the system once equilibrium is reached, which of the following will represent the concentration of ammonia in M? Group of answer choices 6–(X/2) 6–X 6–2X 6+2X 6+Xarrow_forward
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