Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN: 9781337614085
Author: Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher: Cengage,
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**Geometry Problem: 45°-45°-90° Triangle**

**Problem Statement:**
The hypotenuse of a 45°-45°-90° triangle measures \(22\sqrt{2}\) units.

**Diagram Explanation:**
There is a right triangle displayed with two angles marked as 45° each, making it a 45°-45°-90° triangle. The hypotenuse of the triangle is labeled as \(22\sqrt{2}\) units. The legs of the triangle are marked with red lines indicating equal length, characteristic of a 45°-45°-90° triangle.

**Question:**
What is the length of one leg of the triangle?

**Answer Options:**
- \(11\) units
- \(11\sqrt{2}\) units
- \(22\) units
- \(22\sqrt{2}\) units

### Detailed Solution:
In a 45°-45°-90° triangle, the sides have a unique ratio: the legs are equal in length, and the hypotenuse is \(\sqrt{2}\) times the length of each leg. If the hypotenuse \(c\) is given as \(22\sqrt{2}\) units, we can find the length of each leg \(a\) using the following relationship:

\[ c = a\sqrt{2} \]
\[ 22\sqrt{2} = a\sqrt{2} \]

By dividing both sides by \(\sqrt{2}\), we find:

\[ a = \frac{22\sqrt{2}}{\sqrt{2}} = 22 \]

Thus, each leg of the triangle is \(22\) units long.

**Correct Answer:**
- \(22\) units
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Transcribed Image Text:**Geometry Problem: 45°-45°-90° Triangle** **Problem Statement:** The hypotenuse of a 45°-45°-90° triangle measures \(22\sqrt{2}\) units. **Diagram Explanation:** There is a right triangle displayed with two angles marked as 45° each, making it a 45°-45°-90° triangle. The hypotenuse of the triangle is labeled as \(22\sqrt{2}\) units. The legs of the triangle are marked with red lines indicating equal length, characteristic of a 45°-45°-90° triangle. **Question:** What is the length of one leg of the triangle? **Answer Options:** - \(11\) units - \(11\sqrt{2}\) units - \(22\) units - \(22\sqrt{2}\) units ### Detailed Solution: In a 45°-45°-90° triangle, the sides have a unique ratio: the legs are equal in length, and the hypotenuse is \(\sqrt{2}\) times the length of each leg. If the hypotenuse \(c\) is given as \(22\sqrt{2}\) units, we can find the length of each leg \(a\) using the following relationship: \[ c = a\sqrt{2} \] \[ 22\sqrt{2} = a\sqrt{2} \] By dividing both sides by \(\sqrt{2}\), we find: \[ a = \frac{22\sqrt{2}}{\sqrt{2}} = 22 \] Thus, each leg of the triangle is \(22\) units long. **Correct Answer:** - \(22\) units
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