The horizontal and vertical components, respectively, of a force F are given. Compute the magnitude, inclination with the X axis, and the sense of the force F. 1) 450 lb, -750 lb 2) -275 lb, -300 lb

3. Use vector components to find the magnitude and direction of a force vector needed to balance the forces of 400 N @ 145 degrees and 400 N @ 260 degrees.

Angel N (Newton) σN Fg (Newton) σf Weight (Newton 29.3o 1.777   0.8544   1.963 Fill out rest of table. The table is that of slope forces. N = Normal Force got from equation N = m × Az Az = acceleration in z direction Az = (8.795 ± 0.022) m/s2 m = mass  m = (0.2016 kg ± 0.00584 kg) Fg = Force exerted by gravity got from equation Fg = m×|Ay| Ay = acceleration in y direction  Ay = (-4.253 ± 0.015) m/s2 m = mass  m = (0.2016 kg ± 0.00584 kg) The photo is the equation needed to be used to fill in the rest of the table.

A weight of 1800 pounds is suspended from two cables as shown in the figure. What is the tension in the two cables? 30° 45° 1800 pounds What is the tension in the left cable? 1317.7 pounds (Round to one decimal place as needed.) What is the tension in the right cable? 1613.8 pounds (Round to one decimal place as needed.)

The horizontal and vertical components, respectively, of a force F are given. Compute the magnitude, inclination with the X axis, and the sense of the force F.  -300lb, 400lb