The heating element of a coffeemaker operates at 120 V and carries a current of 7.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.252 kg of water from Step 1 The energy required to raise the temperature of an amount of water of mass m from T, = 23.0°C to the boiling point, T = 100°C, is Q= mC,(AT), where the specific heat of water c= 4186 J/kg - °C. We have Q = mc(AT) = m c(T - T) 0.252 kg (4186 /kg · °c)(77, 77 °c) 0.252 - 0.81225 0.812 x 10 ) Step 2 The rate P at which the heating element converts electrical potential energy into the internal energy of the water is P = (AV)I = ( J/s.

The heating element of a coffeemaker operates at 120 V and carries a current of 7.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.252 kg of water from Step 1 The energy required to raise the temperature of an amount of water of mass m from T, = 23.0°C to the boiling point, T = 100°C, is Q= mC,(AT), where the specific heat of water c= 4186 J/kg - °C. We have Q = mc(AT) = m c(T - T) 0.252 kg (4186 /kg · °c)(77, 77 °c) 0.252 - 0.81225 0.812 x 10 ) Step 2 The rate P at which the heating element converts electrical potential energy into the internal energy of the water is P = (AV)I = ( J/s.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter27: Current And Resistance

Section: Chapter Questions

Problem 27.73AP

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