The heat of fusion of ice is 79.7 cal/g. The heat of vaporization of water is 540 cal/g. Report the answer using the correct number of significant figures! 1. How much energy is required to melt 100.0 grams of ice? Mass of ice = 100.0g Heat of fusion of ice: 100,0g|79.7 call-(1970 cal) 2. How much energy is required to vaporize 234.5 g of water? 234.5g | 540cal |= :79.7 cal/g Answer: 7970 cal Mass of 234.59 Heat of vaporization & 540 callg 12 6630, 1.2663X105 (1.3 x 10³ cal Answer: 1.3 x 105 cal 3. If 30.6 calories are required to vaporize 25 g of a substance, what is the heat of vaporization of that substance? mass of substance: 25g Heat vaporization: 30

Evaluate (5x10^0)/((4.0x10^0)*(1.3x10^2)) Your answer should be in scientific notation and with the correct number of significant figures: Note: Your answer is assumed to be reduced to the highest power possible.

(16.1×4200/0.17×830)³

-4.29x^2-2.48x+1.08=0. Solve for unknown

Suppose you are trying to find the volume of a box based on the given measurements for the length, width, and height of the box, where the height was measured in two parts.      length, l = 2.20 in      width, w = 3.71 in      height, h = 10.4 in + 1 in Calculate the height, ℎ, of the box, first keeping all digits, then rounding to the proper number of significant figures. unrounded h = ____in rounded h =____  in  Calculate the volume (V) of the box using V =l x w x h. Round to the proper number of significant figures.  v=_____in3

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(282.7×105)−(1.100×103)]×2.8990 Express your answer to the appropriate number of significant digits.

A 5.000-mLmL urine sample has a mass of 5.025 gg. If the normal range for the specific gravity of urine is 1.003  to 1.030, would the specific gravity of this urine sample indicate that the patient could have type 2 diabetes?

(0.0041×20000.0)+(2817×14). Express your answer to the appropriate number of significant digits.