The greatest common divisor of two positive integers, A and B, is the largest number that can be evenly divided into both of them. Euclid's algorithm can be used to find the greatest common divisor (GCD) of two positive integers. You can use this algorithm in the following manner: 1. Compute the remainder of dividing the larger number by the smaller number. 2. Replace the larger number with the smaller number and the smaller number with the remainder.

Python Help Write (1) the pseudo code, (2) the code, of the following problems: An online bank wants you to create a program that shows prospective customers how their deposits will grow. Your program should read the initial balance and the annual interest rate. Print out the balance after the first three years.

PLEASE MATLAB NOT PYTHON OR OTHERS

Please please please don't copy other solutions with diffrent numbers other than the question please and use python not MATLAB Question asks for x=15 and x=-15 while n ranging between 1 and 80 so I hope to see the code using this numbers Question: We can use the sum of the first n terms of the Taylor series of e^x with a=0 to estimate the value of the exponential function.Using a logarithmic y axis, plot the fractional error in the estimated e^x (compared to numpy.exp(x)) as a function of n (n ranging between 1 and 80) for (a) x = 15 and (b) x = −15. [You can plot the two cases either as different curves on the same plot or in different plots, whichever is clearer.] Please answer this question *FULLY* in python showing the whole code I would appreciate your help alot

Help please with how to code this in python

Question 15 What is the output of the following program? temp_Fahrenheit = 36 if temp_Fahrenheit 80: print('It is hot outside') else: pass print('It must be a nice day') It is cold outside O It is hot outside It must be a nice day No output because of the pass statement < 1 2 3 4 5 O Mark this question 6

using ternary operation to replace the following python code: c='a' v=none if c=='a':                  v='A' else                 v=1