College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Text Transcription and Graph Explanation for Educational Website**

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**2. Problem Statement**

The graph shows a plot of the x component of the spring force as a horizontal spring is stretched and compressed through its equilibrium position. Recall that the spring force is \( F_{\text{spr},x} = -k(x - x_{\text{eq}}) \).

**a. Question 1:** What is the equilibrium length of this spring?

**b. Question 2:** What is the spring constant?

**c. Question 3:** What is the change in elastic potential energy as this spring, initially compressed to a length of 0.3 meters, is stretched to 0.9 meters? *The answer is not 4.5 joules.*

**d. Question 4:** Work done against the spring force can be stored as elastic potential energy. Therefore, \(\Delta E_{\text{elastic}}\) is the negative of the work by the spring force. Use the area "under" the \( F_x \) vs. \( x \) graph to find the work done by the spring force. Check that this is the negative of your answer to c.

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**Graph Explanation**

The graph is a plot of the force (\( F_x \) in Newtons) versus the spring length (in meters). The spring force is shown as a linear line decreasing from 0.3 meters to 0.9 meters, ranging from 10 N to -15 N, respectively. It depicts how the force exerted by the spring changes as it is stretched or compressed around its equilibrium position. The line's slope is negative, indicating the restoring nature of the spring force as it follows Hooke’s Law. 

- **Horizontal Axis:** Represents the spring length in meters, ranging from 0.3 to 0.9 meters.
- **Vertical Axis:** Represents the force (\( F_x \)) in Newtons, ranging from 10 N to -15 N.
- The slope of the line on the graph indicates the spring constant (\( k \)).

This visual representation helps in understanding the relationship between spring force and displacement from equilibrium, as well as calculating potential energy changes and work done.
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Transcribed Image Text:**Text Transcription and Graph Explanation for Educational Website** --- **2. Problem Statement** The graph shows a plot of the x component of the spring force as a horizontal spring is stretched and compressed through its equilibrium position. Recall that the spring force is \( F_{\text{spr},x} = -k(x - x_{\text{eq}}) \). **a. Question 1:** What is the equilibrium length of this spring? **b. Question 2:** What is the spring constant? **c. Question 3:** What is the change in elastic potential energy as this spring, initially compressed to a length of 0.3 meters, is stretched to 0.9 meters? *The answer is not 4.5 joules.* **d. Question 4:** Work done against the spring force can be stored as elastic potential energy. Therefore, \(\Delta E_{\text{elastic}}\) is the negative of the work by the spring force. Use the area "under" the \( F_x \) vs. \( x \) graph to find the work done by the spring force. Check that this is the negative of your answer to c. --- **Graph Explanation** The graph is a plot of the force (\( F_x \) in Newtons) versus the spring length (in meters). The spring force is shown as a linear line decreasing from 0.3 meters to 0.9 meters, ranging from 10 N to -15 N, respectively. It depicts how the force exerted by the spring changes as it is stretched or compressed around its equilibrium position. The line's slope is negative, indicating the restoring nature of the spring force as it follows Hooke’s Law. - **Horizontal Axis:** Represents the spring length in meters, ranging from 0.3 to 0.9 meters. - **Vertical Axis:** Represents the force (\( F_x \)) in Newtons, ranging from 10 N to -15 N. - The slope of the line on the graph indicates the spring constant (\( k \)). This visual representation helps in understanding the relationship between spring force and displacement from equilibrium, as well as calculating potential energy changes and work done.
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