The first quadrant of the x y coordinate plane is given. There is one curve on the graph. The curve starts at the point (0, 600), goes down and right becoming less steep, passes through the approximate points (10, 400), (20, 300) and (30, 250), and reaches a minimum at the point (40, 200). The curve then goes up and right becoming more steep, passes through the approximate points (50, 400) and (60, 700), becoming less steep, reaches a maximum at the approximate point (70, 900) where it changes direction and goes down and right. The curve exits the window at the XX point (80, 800).20" 40 60 The graph of a function f is shown. y 800 400 x 0 20 40 60 (a) Find the average rate of change of f on the interval [50, 60]. (b) Identify an interval on which the average rate of change of f is 0. ○ [10, 50] [10, 40] ○ [20, 40] ○ [0, 80] ○ [0, 60] (c) Compute the following. f(40) - f(0) 40 0 What does this value represent geometrically? the slope of the tangent line at (20, f(20)) ◇ the slope of the line segment from (0, f(0)) to (40, f(40)) O the slope of the tangent line at (40, f(40)) the slope of the tangent line at (0, f(0)) (d) Estimate the value of f' (50). (e) Is f'(10) > f'(30)? Yes No f(80) - f(40), (f) Is f'(60) > 80-40 Yes No Explain. The slope of the tangent line at x = 60, f'(60), is less than the slope of the line passing through (40, f(40)) and (80, f(80)). The slope of the tangent line at x = 40, f'(40), is less than the slope of the line passing through (60, f(60)) and (80, f(80)). The slope of the tangent line at x = 60, f'(60), is greater than the slope of the line passing through (40, f(40)) and (80, f(80)). The slope of the tangent line at x = 80, f'(80), is greater than the slope of the line passing through (40, f(40)) and (60, f(60)). The slope of the tangent line at x = 80, f'(80), is less than the slope of the line passing through (40, f(40)) and (60, f(60)).
The first quadrant of the x y coordinate plane is given. There is one curve on the graph. The curve starts at the point (0, 600), goes down and right becoming less steep, passes through the approximate points (10, 400), (20, 300) and (30, 250), and reaches a minimum at the point (40, 200). The curve then goes up and right becoming more steep, passes through the approximate points (50, 400) and (60, 700), becoming less steep, reaches a maximum at the approximate point (70, 900) where it changes direction and goes down and right. The curve exits the window at the XX point (80, 800).20" 40 60 The graph of a function f is shown. y 800 400 x 0 20 40 60 (a) Find the average rate of change of f on the interval [50, 60]. (b) Identify an interval on which the average rate of change of f is 0. ○ [10, 50] [10, 40] ○ [20, 40] ○ [0, 80] ○ [0, 60] (c) Compute the following. f(40) - f(0) 40 0 What does this value represent geometrically? the slope of the tangent line at (20, f(20)) ◇ the slope of the line segment from (0, f(0)) to (40, f(40)) O the slope of the tangent line at (40, f(40)) the slope of the tangent line at (0, f(0)) (d) Estimate the value of f' (50). (e) Is f'(10) > f'(30)? Yes No f(80) - f(40), (f) Is f'(60) > 80-40 Yes No Explain. The slope of the tangent line at x = 60, f'(60), is less than the slope of the line passing through (40, f(40)) and (80, f(80)). The slope of the tangent line at x = 40, f'(40), is less than the slope of the line passing through (60, f(60)) and (80, f(80)). The slope of the tangent line at x = 60, f'(60), is greater than the slope of the line passing through (40, f(40)) and (80, f(80)). The slope of the tangent line at x = 80, f'(80), is greater than the slope of the line passing through (40, f(40)) and (60, f(60)). The slope of the tangent line at x = 80, f'(80), is less than the slope of the line passing through (40, f(40)) and (60, f(60)).