The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x (also in arbitrary units). Which of the choices below correctly describes the orientation of the x-component of the electric field along the x-axis? V(x) $.5 25 15 0.5 -2 -1.5 -1-0.5 0.5 1 1.5 2 x' O Ex is negative from x = -2 to x = 0, and positive from x =0 to x 2. O none of the given choices O Ex is positive from x = -2 to x = 2. O Ex is negative from x = -2 to x = 2. O Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.

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Chapter1: Units, Trigonometry. And Vectors
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The graph in the figure shows the variation of the electric potential
V(x) (in arbitrary units) as a function of the position x (also in
arbitrary units). Which of the choices below correctly describes the
orientation of the x-component of the electric field along the x-axis?
V(x)
4.5
$.5
2.5
15
+
0.5
-2 -1.5 -1 -0.5
0.5 1 1.5 2 x
O Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2.
none of the given choices
O Ex is positive from x = -2 to x = 2.
O Ex is negative from x = -2 to x = 2.
%3D
Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.
%3D
Transcribed Image Text:The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x (also in arbitrary units). Which of the choices below correctly describes the orientation of the x-component of the electric field along the x-axis? V(x) 4.5 $.5 2.5 15 + 0.5 -2 -1.5 -1 -0.5 0.5 1 1.5 2 x O Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2. none of the given choices O Ex is positive from x = -2 to x = 2. O Ex is negative from x = -2 to x = 2. %3D Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2. %3D
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