The graph from Fig. I shows the I-V characteristics of a diode. Potential Difference (V) Fig. 1 Explain why? Assist your a) At which points marked on the graph is the resistance of the diode is highest? explanation using Fig. 2. P type N type Fig. 2 b) At which points marked on the graph is the resistance of the diode is lowest? explanation using the Fig. 3. Explain why? Assist your P type N type Fig. 3 c) At which points marked on the graph, junction capacitance will be occurred? Explain why? - Current (D

The graph from Fig. I shows the I-V characteristics of a diode. Potential Difference (V) Fig. 1 Explain why? Assist your a) At which points marked on the graph is the resistance of the diode is highest? explanation using Fig. 2. P type N type Fig. 2 b) At which points marked on the graph is the resistance of the diode is lowest? explanation using the Fig. 3. Explain why? Assist your P type N type Fig. 3 c) At which points marked on the graph, junction capacitance will be occurred? Explain why? - Current (D

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter59: Motor Startup And Troubleshooting Basics

Section: Chapter Questions

Problem 12SQ: How is a solid-state diode tested? Explain.

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The circuit below was connected to investigate the relation between the voltage and current in the diode. For each setting of the voltage source, E, the current through and the voltage across the diode were recorded and tabulated in the table below. a) Find the DC resistance of the diode when the voltage across it is 0.57 V. Repeat the calculation when the voltage across the diode is 0.66 V. Compare the two answers. b) Find the average resistance of the diode when an AC generator causes the voltage across the diode to vary between 0.57 and 0.63 V. c) Derive an expression for the AC (dynamic) resistance of the diode, using Shockley's equation, and use it to find the diode's AC resistance at room temperature when V, is equal to 0.62 V. Hint: Write down the Shockley's equation and take the derivative, which corresponds to the slope (inverse of AC resistance) of the tangent at a point. R + I, E Vp Vp (V) Ip (mA) 0.705 1.04 0.56 0.61 0.62 0.63 0.66 51.1 0.67 75.3 0.55 0.57 0.68 1.54 7.33…
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