The government reports that the literacy rate is 52%. A non-governmental organization believes it to be less. The organization takes a random sample of 600 inhabitants and obtains a literacy rate of 42%. Perform the relevant test at the 0.5% (one-half of 1%) level of significance.

What is the t statistic for the top 3% for a sample size of 19.

90%

In a random sample of 68 people,17 are classified as​ "successful."   a. Determine the sample​ proportion, p, of​ "successful" people. b. If the population proportion is 0.70​,determine the standard error of the proportion.

A polisher wishes to estimate the proportion of United States voters who favor capital punishment. How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 3%

Please help me in answering the following practice question:Given a random sample of the amount of protein (in gram) in one bag of snack food: 0.95, 0.85, 0.92, 0.95, 0.93, 0.86, 1, 0.92, 0.85, 0.81, 0.78, 0.93, 0.93, 1.05, 0.93, 1.06, 1.06, 0.96, 0.81, 0.96 Here, it is assumed that the amount of protein in the snack is normal. How would I calculate a 98% two-sided confidence interval for the average amount of protein in one bag?Thank you for your help in advance!

A random sample of employees participating in a company fitness program were asked how many days they logged an exercise activity in the past month. Their responses are reported in the histogram below.Based on the histogram above, what is the class width? Clas width = ? Days What is the sample size? Sample size = ? employees

Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…