The given frame is subjected to the applied loads P and Q.Note that members ABC and CDE are pin-connected at C.a) Draw the FBDs of all members.Ab) Determine the force in each link (AF, BG, DG, and EH).FNeglect the weight of the members.Parameters*2 0DA B C12 10 2 13P= 100+ (ECD) x 0.1Q = 100+ (BAC) x 0.1e = 30 x (P/Q)P = 100 + (534) x 0.1 = 153.4 kNQ=100+ (312) x 0.1 = 121.3 kNe = 30 x (153.4/121.3) = 37.94°14E5E2aB3OGHOHED8a2a

Given, Load P=153.4 kN Load Q=121..3 kN Angle θ=37.94°

The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. A b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameters * * 2 0 A B C 2 3 P=100+ (ECD) x 0.1 Q = 100+ (BAC) x 0.1 e = 30 x (P/Q) 2 0 2 P=100+ (534) x 0.1 = 153.4 kN Q=100+ (312) x 0.1 = 121.3 kN e 30 x (153.4/121.3) = 37.94° = D4 E5 5 2a I B W 7 a I (0) I HE C D 8 a a 2a

The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. A b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameters * * 2 0 A B C 2 3 P=100+ (ECD) x 0.1 Q = 100+ (BAC) x 0.1 e = 30 x (P/Q) 2 0 2 P=100+ (534) x 0.1 = 153.4 kN Q=100+ (312) x 0.1 = 121.3 kN e 30 x (153.4/121.3) = 37.94° = D4 E5 5 2a I B W 7 a I (0) I HE C D 8 a a 2a

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load on Structures

Civil engineers primarily deal with beams in their day-to-day applications. A beam is a structural member that resists shear loadings. There are various types of beams such as cantilever beam, simply supported beam, and over the hanging beam. All these beams have a different end and loading conditions.

Question

The given frame is subjected to the applied loads P and Q.
Note that members ABC and CDE are pin-connected at C.
a) Draw the FBDs of all members.
A
b) Determine the force in each link (AF, BG, DG, and EH).
F
Neglect the weight of the members.
Parameters
*
2 0
D
A B C
1
2 10 2 1
3
P= 100+ (ECD) x 0.1
Q = 100+ (BAC) x 0.1
e = 30 x (P/Q)
P = 100 + (534) x 0.1 = 153.4 kN
Q=100+ (312) x 0.1 = 121.3 kN
e = 30 x (153.4/121.3) = 37.94°
14
E5
E
2a
B
3
OG
HO
HE
D
8
a
2a

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