The gas phase reaction A→B+2C is carried out in a constant volume batch reactor (V=25 L). Twenty moles of A with 80% purity (the remainder is inert) are introduced into the reactor. Calculate the time to reduce the concentration of A to 0.1 mol/L if the reaction is first order with k=0.524 min-1. Calculate the time required to consume 10 mols of A if the reaction is second order and k=0.982 L/mol.h. If the temperature is 150°C, what is the total initial pressure? What is the final total pressure if the reaction occurs in its entirety? Explain why pressure varies in this situation.

In a batch reactor, reactant A is steadily converted into product B. The initialconcentration of reactant A is 100 mg/L. During a 10-hour reaction course, it wasobserved that the concentration of A in the reactor decreased at a constant rate of 10mg/L per hour. Based on the result, you can determine that the transformation reactionA→B follows ( ) with respect to reactant A.

Why does the product (a•b), rather than the sum (a + b) appear in the Law of Mass Action? This is sometimes brought up to demonstrate how/why nonlinear terms arise in differential equations. The law of mass action states that The rate of a chemical reaction involving an interaction of two or more chemical species is proportional to the product of the concentrations of the given species.  This is NOT an assignment...I'm just curious and trying to understand mathematical relations better. Thanks!

I need help with this problem. I want to see detailed steps.

help me here please, this is my last attempt. Thanks!

Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = = 1.8 × 10-5 [500.0] [0.200] RESET [5.00] [1.0 × 10-9] [1.0 × 10-9] [1.8 × 10-5] [x + 5.00] [x + 1.0 × 10] [x-1.0 x 10 x + 1.0 × 10-] [x-1.0 × 10-] [x+1.8 × 10] [x-1.8 × 10%] [0] [x-5.00] < PREV 1 2 3 Based on your ICE table (Part 1) and the equilibrium expression, Ka (Part 2), determine the original mass of solid CH3COONa added to create this buffer solution. MNACH3COO g 0 0.360 30 21 43 11 15 36 x 10' 59 x 105 43 x 105 RESET 59 50