The function has v imaginary zero(s). This is because the graph shows v real zero(s) and the function has a total of v zeros.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.4: Fractional Expressions
Problem 72E
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This equation is about fundamental theorem of algebra. Determine the number of imaginary zeros for the function with the given degree of 3 and graph, image is shown below.
The function has
v imaginary zero(s). This is because the graph shows
v real zero(s) and the function has a total of
v zeros
Transcribed Image Text:The function has v imaginary zero(s). This is because the graph shows v real zero(s) and the function has a total of v zeros
Ay
40
20
-4/-2
4x
20
-20
Transcribed Image Text:Ay 40 20 -4/-2 4x 20 -20
Expert Solution
Step 1

No. of real zeros + No. Of imaginary zeros = Total no. Of zeros. 

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