The function, f(x) = –2x² + x + 5, is in standard form. The What are the zeros of the function quadratic equation is 0 = -2x + x + 5, where a = -2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. f(x) = x + 5 – 2x2? x = -1±/4T -4 5. Solve using the quadratic formula. O x= 1±/41 -4 -b±yb²- 4ac_ x = 2a x = -1±/39 - 4 X = 1±/39 - 4

Solve the following quadratic function to find the x-intercepts: f(x) = x² - 6x +9 x = 3 x = -3 and 3 x = 9 and -6 x = -5 and -1

Consider the quadratic function q(x) = x 2 + 6x − 16. Respond to the following (in any order): (a) Show how to locate the coordinates of the vertex. (b) Write an equation for the axis of symmetry. (c) Determine the x-intercepts and the y-intercept exactly. (d) Sketch a graph of the function showing the vertex, axis of symmetry, x-intercepts, and y-intercept. (e) Write an equation for the function, p, that results from shifting the graph of the function q to the left 4 units and up 3 units. (f) Graph the function p on the same axes as the function q.

Fill in the blank with the appropriate number. If the vertex of y= -x +4x -4 lies on the x-axis, then the quadratic equation -x +4x-4=0 has (1) solution(s).