The function f (x, y) = x³ - 3x² y + 3xy²-y3-11 22-2xy +49 y2 - 16 x + 208 y + 131 has a critical point on the x-axis. (a) (i) Enter f (x,0) = (ii) Enter fy (a,0) = (b) Enter the x-coordinate of the critical point, where both these derivatives are zero. Number (c) Enter the matrix [fax fxy] at that point.
The function f (x, y) = x³ - 3x² y + 3xy²-y3-11 22-2xy +49 y2 - 16 x + 208 y + 131 has a critical point on the x-axis. (a) (i) Enter f (x,0) = (ii) Enter fy (a,0) = (b) Enter the x-coordinate of the critical point, where both these derivatives are zero. Number (c) Enter the matrix [fax fxy] at that point.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter14: Discrete Dynamical Systems
Section14.3: Determining Stability
Problem 13E: Repeat the instruction of Exercise 11 for the function. f(x)=x3+x For part d, use i. a1=0.1 ii...
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