The function f (1, y) = +y- 3zy O has a saddle point at (1, 1) O has a local maximum at (0, 0) O has a local minimum at (1, 1) O has a local maximum at (1, 1)
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- Repeat the instruction of Exercise 11 for the function. f(x)=x3+x For part d, use i. a1=0.1 ii a1=0.1 11. Consider the function f(x)=4x2(1x) a. Find any equilibrium points where f(x)=x. b. Determine the derivative at each of the equilibrium points found in part a. c. What does the theorem on the Stability of Equilibrium points tell us about each of the equilibrium points found in part a? d. Find the next four iterations of the function for the following starting values. i. a1=0.4. ii. a2=0.7 e. Describe the behavior of successive iteration found in part d. f. Discuss how the behavior found in part d relates to the results from part c.Let f(x,y)=y22x2y+4x3+20x2. The only critical points are (2,4), (0,0), and (5,25). Which of the following correctly describes the behavior of f at these points? Source: Society of Actuaries. a. (2,4): local relative minimum (0,0): local relative minimum (5,25): local relative maximum b. (2,4): local relative minimum (0,0): local relative maximum (5,25): local relative maximum c. (2,4): neither a local relative minimum nor local relative maximum (0,0): local relative maximum (5,25): local relative minimum d. (2,4): local relative maximum (0,0): neither a local relative minimum nor local relative maximum (5,25): local relative minimum e. (2,4): neither a local relative minimum nor local relative maximum (0,0): local relative minimum (5,25): neither a local relative minimum nor local relative maximumThe function f has continuous second derivatives, and a critical point at (-8, -7). Suppose frz(-8, -7) = -16, f(-8,-7) = -8, f(-8,-7) = -4 Then the point (-8, -7): O A. is a local maximum O B. cannot be determined C. is a saddle point O D. is a local minimum O E. None of the above
- 2. Examine the function f(x, y) = x' - 15xy +y³ +7 for relative extrema and saddle points. a. saddle point: (0, 0, 7): relative minimum: (5, 5, –118) b. relative minimum: 0. 0, ); relative maximum: (5, 5, -118) c. saddle points: (0, 0, 7) (5, 5, –118) d. saddle point: (5, 5, –118). relative minimum: (0, 0, 7) (5, 5,-118). relative maximum: (0, 0, 7) e. relative minimum:find the local max and min values and saddle points of the function f(x,y)=xy*(1-x-y)Apply a second derivative to identify a critical points as a local maximum, local minimum or saddle point for a function. Suppose that f(x, y) = 3x + 3y - lay then the minimum is
- Find the local maximum, local minimum, and saddle points of the function f(x,y) = x2 + xy? - 2x+1 Maximum at (1.0) Minimum at (0.12) Saddle Point at (0,-12) Saddle Point at (1,0) Minimum at (0.v2) Maximum at (0.-12) O Minimum at (1,0) Saddle Point at (0,12) Saddle Point at (0,-12) O Maximum at (1,0) Degenerated at (0,12) Degenerated at (0,-12)9) Find the critical points and identify their types as Min., Max., Saddle point, or neither. f(x, y) = xye-x²-yFind values of a and b so that the function f(x) = x + ax + b has a local minimum at the point (7,-4). a = b =
- The function f (x, y) = 1 +y-3zy has a local minimum at (1, 1) has a local maximum at (0, 0) has a saddle point at (1, 1) O has a local maximum at (1, 1)5-(15 p.) Find all local maximum, local minimum and saddle points of f(1, y) = 6z – 2r+3y² + 6ry12) Please show all work/steps Test for relative maxima and minima.z= (x^2)+16xy +(y^2)-252x Which one of the following is correct?A) saddle point at (2, –16, – 756)B) saddle point at (–2,16, 252)C) saddle point at (0, 0, 0)D) relative minimum at (–2, –16,1276)E) relative minimum at (40, – 256, –106784)