The function f-1 is an inverse function of ƒ if f(ƒ −¹(x)) = f−¹(f(x)). To verify, consider f(x) = 5x f(f−¹(x)) = f−¹(f(x)) f(F-¹(x)) = f (X + 8) 5 Hence, = 5(x + 8) - = x + 8 - 8 || 8 and f-¹(x): ƒ−¹(f(x)) = f−¹( || f(ƒ −¹(x)) = ƒ −¹(f(x)) 8 (5x – 8) + 8 5 = X + 8 5 - 8)

Let f(x) f-1(-7) = x +3 x + 9 О acer

When doing composite functions, if I have a problem that says f(x)=x/x-5 and g(x)=-3/x/ How do I simplify my solution for f(g(x)). I got the answer -3/x/x-5

Let x+1 f(x) x+8 ƒ¯¹( − 4) = =