The function f-1 is an inverse function of ƒ if f(ƒ −¹(x)) = f−¹(f(x)). To verify, consider f(x) = 5x f(f−¹(x)) = f−¹(f(x)) f(F-¹(x)) = f (X + 8) 5 Hence, = 5(x + 8) - = x + 8 - 8 || 8 and f-¹(x): ƒ−¹(f(x)) = f−¹( || f(ƒ −¹(x)) = ƒ −¹(f(x)) 8 (5x – 8) + 8 5 = X + 8 5 - 8)

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