The free energy change for the following reaction at 25 °C, when [Cu²']= 2.55×10° M and [Fe°"]= 1.15 M, is 74.8 kJ: Cu²+(2.55×103 M) + Fe²*(aq)- →Cu*(aq) + Fe3*(1.15 M) AG = 74.8 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?

The free energy change for the following reaction at 25 °C, when [Cu²']= 2.55×10° M and [Fe°"]= 1.15 M, is 74.8 kJ: Cu²+(2.55×103 M) + Fe²(aq)- →Cu(aq) + Fe3*(1.15 M) AG = 74.8 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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