The following table lists results from an experiment designed to test the ability of dogs to use their extraordinary sense of smell to detect malaria in samples of ch presented at an annual meeting of the American Society of Tropical Medicine, by principal investigator Steve Lindsay). The accompanying information shows the calculator results for the experiment. Assume that the hypothesis test requirements are all satisfied. Complete parts (a) through (c) below. Malaria Was Present 123 52 Malaria Was Not Present 131 14 Dog Was Correct Dog Was Wrong iClick the icon to view the hypotheses and the calculator output.
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- What is an experiment?What is meant by the sample space of an experiment?6.24 Sleep deprivation, CA vs. OR, Part II. Exercise 6.22 provides data on sleep deprivation rates of Californians and Oregonians. The proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. (a) Conduct a hypothesis test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. (Reminder: Check conditions) (b) It is possible the conclusion of the test in part (a) is incorrect. If this is the case, what type of error was made?
- BASED ON THE CASE SCENARIO, ANSWER QUESTION 55-60In the leg ulcer trial, 233 patients with venous leg ulcers were randomly assigned to intervention group using a new regime treatment (Group 1) or the control group using the standard care (Group 2). Patients were treated and followed up for 3 months.The researcher would like to determine if there is any association between types of treatment for leg ulcer and ulcer status (healed or not healed) at 3 months. Which statistical method is appropriate for the above case? 1. Pearson’s correlation2. Chi square goodness of fit test3. Simple linear regression4. Chi square test for independenceDid the ductility of the wire change after soaking it to an acid solution? Infer from the data below: Ductility before soaking Ductility after soaking 2563 2405 2564 2406 2565 2407 2566 2408 2567 2409 2452 2693 2453 2694 2454 2695 2455 2696 2456 2697 2634 2589 2635 2590 2636 2591 2637 2592 1.) Create a null and alternative hypothesis 2.) Is there a significant change before and after soaking? Prove it using computationsA researcher tracked depression symptoms in new mothers from the USA, Mexico, and Canada. Determine if there are any differences in the average number of depressive symptoms between the three countries. Conduct an ANOVA test using alpha = .05 and the eight steps of hypothesis testing. Include the full source table in step 5. NOTE: Conduct a post-hoc test even if you fail to reject the null. USA Mexico Canada 15 15 12 14 17 10 13 14 12 14 15 11 13 19 9 15 18 8 16 16 11
- Worksheet #15 Name: Hypothesis Testing 1. A genetic experiment involving peas yielded one sample of offspring consisting of 434 green peas and 134 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. a. What are the null and alternative hypotheses? b. What is the test statistic? C. What is the P-value? d. What is the conclusion about the null hypothesis? A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, . B. Reject the null hypothesis because the P-value is less than or equal to the significance level,. C. Fail to reject the null hypothesis because the P-value is greater than the…A car leasing firm's records indicate that the mean number of miles driven annually in its cars has been about 17,500 miles. The firm suspects that this number has decreased this past year. Suppose that the firm wishes to choose a small sample of driving distances from the past year and carry out a hypothesis test for its suspicion. State the null hypothesis H0 and the alternative hypothesis H1 that it would use for this test.You recently completed an experiment concerning the effects of carbs on happiness. One group of 11 people are assigned a high carb diet, another group of 11 people are assigned a moderate-high carb diet, another group of 11 people are assigned a moderate-low carb diet, and a final group of 11 people are assigned a low carb diet. If I find that I fail to reject the null hypothesis, what might my next step be? Group of answer choices Change my analysis and alpha to make the finding significant and then run post-hoc tests. 1. Run multiple dependent measures t-tests to see if there are any significant differences between particular groups 2. Run multiple independent samples t-tests to see if there are any significant differences between particular groups 3. Change my hypothesis to see if I can find something significant with a different hypothesis for this study 4. Run home and binge-watch Bridgerton because there is nothing else that should be done statistically
- (...) Dairy cows - The USDA collects and distributes a wide variety of data about agriculture in the United States. One statistic reported each year is the number of milk cows (in thousands) in each state. A random sample of 10 states is selected, with the number of milk cows reported in both 2011 and 2015. 1. Which hypotheses should be used to conduct the test? diff=0 vs. H₁ : 0 vs. Ha diff 5.7 20.202 mean sd 2015 19 47 125 195 14 1279 14 408 2011 19 45 119 188 14 1265 18 366 329 323 98 94 246.1 251.8 379.881 385.58 Difference 0 2 6 7 0 14 -4 42 -6 -4 5.7 14.111 3. Based on the p value we have Little evidence that the null model is not a good fit for our observed data. 4. Construct a 99% confidence interval for the mean difference in the number of milk cows (in thousands) between 2011 and 2015.A comparison between species: Biologists wish to compare the prevalence of a genetic mutation across two species of Neema Toads. In a sample of 6 Neema Toads of Species I, 0.8% had the mutation while in a sample of 14 Neema Toads of Species II, 0.7% showed the mutation. Is there significant evidence to suggest a difference in the prevalence of the mutation across the two species? Conduct a hypothesis test at a significance level of α=0.01α=0.01.a) The hypotheses for this test are: H0: pI - pII = 0Ha: pI - pII ≠ 0 H0: pI - pII = 0Ha: pI - pII < 0 H0: pII = 0.008Ha: pII ≠ 0.008 H0: pI - pII = 0Ha: pI - pII > 0 What is the test statistic for this test?test statistic = (Report answer accurate to 2 decimal places.)What is the p-value for this test?p-value = (Report answer accurate to 4 decimal places.)The decision reached is Fail to reject H0 Reject H0 and accept Ha As such, the final conclusion is that The prevalence of the mutation is the same for both species. There is…The owner of a local golf course wants to examine the difference between the average ages of males and females that play on the golf course. Specifically, he wants to test if the average age of males is different from the average age of females. If the owner conducts a hypothesis test for two independent samples and calculates a p-value of 0.2003, what is the appropriate conclusion? Label males as group 1 and females as group 2. Question 14 options: 1) We did not find enough evidence to say the average age of males is less than the average age of females. 2) We did not find enough evidence to say the average age of males is larger than the average age of females. 3) The average age of males is equal to the average age of females. 4) We did not find enough evidence to say a significant difference exists between the average age of males and females.…