Thank u for the help The following reaction\[ 2\text{H}_2\text{S(g)} \rightleftharpoons 2\text{H}_2\text{(g)} + \text{S}_2\text{(g)}, \quad K_c = 1.67 \times 10^{-7} \text{ at } 800^\circ \text{C} \]is carried out at 800 °C with the following initial concentrations: $[ \text{H}_2\text{S} ] = 0.100 \, \text{M},$ $[ \text{H}_2 ] = 0.100 \, \text{M},$ and $[ \text{S}_2 ] = 0.00 \, \text{M}.$ Find the equilibrium concentration of $\text{S}_2$.**Express the molarity to three significant figures.**

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Answered: The following reaction 2H₂S(g) = 2H₂(g)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The following reaction

\[ 2\text{H}_2\text{S(g)} \rightleftharpoons 2\text{H}_2\text{(g)} + \text{S}_2\text{(g)}, \quad K_c = 1.67 \times 10^{-7} \text{ at } 800^\circ \text{C} \]

is carried out at 800 °C with the following initial concentrations: $[ \text{H}_2\text{S} ] = 0.100 \, \text{M},$ $[ \text{H}_2 ] = 0.100 \, \text{M},$ and $[ \text{S}_2 ] = 0.00 \, \text{M}.$ Find the equilibrium concentration of $\text{S}_2$.

**Express the molarity to three significant figures.**

Expert Solution

Step 1: Interpretation of datas :

$bold italic R bold italic e bold italic a bold italic c bold italic t bold italic i bold italic o bold italic n bold space bold colon bold space bold space 2 space H subscript 2 S left parenthesis g right parenthesis space rightwards harpoon over leftwards harpoon 2 H subscript 2 left parenthesis g right parenthesis space plus S subscript 2 left parenthesis g right parenthesis K subscript c equals 1.67 cross times 10 to the power of negative 7 end exponent I n i t i a l space c o n c e n t r a t i o n space colon left square bracket H subscript 2 S right square bracket equals 0.100 space M left square bracket H subscript 2 right square bracket equals 0.100 M left square bracket S subscript 2 right square bracket equals 0.00 space M bold italic O bold italic b bold italic j bold italic e bold italic c bold italic t bold italic i bold italic v bold italic e bold space bold colon C a l c u l a t i o n space e q u i l i b r i u m space c o n c e n t r a t i o n space o f space S subscript 2$

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