The following probability distribution shows the number of years the students in our class have been in college (1-freshman, 2-sophomore, 3=-junior, 4-senior). In order to make the following probability distribution valid, what does the probability of being a junior need to be? a. 0.01 Ob. 0.13 Oc. 0.10 O d. 0.05 x (number of years in college) Probability 1 2 3 4 0.36 0.46 0.05

Q: Find (+72+6) dz + C

A:

Q: Estimate N if (L, R, d) = (0.5, 0.15, 8) and R is increased from0.15 to 0.17.

A: Given, N=L,R,D=0.5,0.15,8 if R incresed from 0.15 to 0.17 N=0.5, 0.17, 8

Q: 1. Let A : Find A20. x 0

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Q: 376 61)22936

A:

Q: 4 2. lim 8 g० ४-०

A: Given,          limv→2v2-4v3-8

Q: 4.) 40- (8 x 9) 3+ 10

A: Given expression: 40-8×9÷3+10

Q: What is j raise to 6+4j?

A: Find 6+4jj.

Q: 8. arctan (-1)

A:

Q: t = x -N 69.니7-70 28.26 30

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Q: 5 *-1

A:

Q: あ。(12イ45 bt-ef e

A: 2x+53ax-53

Q: x+ 5 = 20 Find x.

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Q: 119 15. 16. 17. (3x + 10)° (5x - 19)° 629 (8x+ 3) (7x + 12) (2x + 5)°

A: Solving for x.

Q: 5 2. 14x dx

A:

Q: 3 3. tan ydy

A: Consider the given integral. I=∫π33π4tan8ydy First calculate the integral. I1=∫tan8ydy

Q: 2) Use linearization to approximate the value of 7.99 +(7.99)².

A:

Q: Which of the following is equal to C(300,40)

A: We can make it easier for you.

Q: 12

A:

Q: / Find A" if 1 2 3 A = 4'1 5 1 %3D

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Q: X 이 5 ⑦

A: Consider the triangle,

Q: 4.25a - 7.5a + 5 + 3.2a

A:

Q: 8 Evaluate for (3x² -7x+4

A: We have to use the concept of derivatives

Q: 2 |12-x²+ x) dz. -3

A: Given: ∫-32(2-x2+x)dx

Q: 2 4. Express 989 = 23 43 in the form x² + xy + 5y².

A: The given number is 989. The objective is to express the given number in the form of x2+xy+5y2.

Q: Enter the value of L- 1.27].

A: Floor value of x  is given as the greatest integer that is less than or equal to x

Q: 97 45. -x³dx +

A:

Q: 8 n (-2) n 3231 7zZ

A:

Q: 8 dp- 12 x" -1 Evaluate

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Q: 18.

A:

Q: (1+2 In æ)4 6.

A: topic - indefinite integral

Q: PO 5.5. -X².11+ y²) xe dx dy

A:

Q: 9. Solve for x. 9.

A: Topic = triangle x = 9

Q: 2. Evaluate In(-3).

A: We have to find ln(-3).

Q: 10. 15 > 19 + 0.2(5x – 90)

A: The given inequality: 15>19+0.2(5x-90)

Q: 5a2 – 14.x + 6 d.x 13.) x3 -3x2

A:

Q: 1. (-√6 + i√2)*

A: To simplify: -6+i24=-6+i222=(-6)2-262i+(i2)22=6-23(2)2i+2i22=6-43i-22=(4-43i)2

Q: .72+40

A: