The following observations are lifetimes (days) subsequent to diagnosis for individuals suffering from blood cancer. 115 182 256 419 442 462 516 739 744 789 808 865 924 984 1026 1062 1063 1165 1192 1222 1222 1251 1479 1578 1925 1277 1291 1358 1369 1409 1455 1519 1578 1599 1603 1605 1696 1736 1799 1815 1853 1899 1966 (a) Can a confidence interval for true average lifetime be calculated without assuming anything about the nature of the lifetime distribution? Explain your reasoning. [Note: A normal probability plot of the data exhibits a reasonably linear pattern. O Yes, the range is sufficiently large enough for the confidence interval to be reasonable. Yes, the sample size is large enough for the confidence interval to be reasonable. No, we need to assume that the population is normally distributed. No, the sample size is not large enough for the confidence interval to be reasonable. O No, the range is not large enough for the confidence interval to be reasonable. (b) Calculate and interpret a confidence interval with a 99% confidence level for true average lifetime. [Hint: x = 1192.0 and s = 506.5.] (Round your answers to one decimal place.) Interpret the resulting interval. We are 99% confident that this interval does not contain the true population mean. We are 99% confident that the true population mean lies below this interval. We are 99% confident that this interval contains the true population mean. We are 99% confident that the true population mean lies above this interval.

What are the specific calculator steps to solve this problem. I already have the answer, but I need the procedure. I don't have a scietinfic calculator and I don't know how to use one. I need to show my work for my exam. Please help. Thank you. 1-(1+0.005)-12*10

How do you find that missing number?

What is the value of t0.025,22?