Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Transcribed Image Text:The following masses m, are located at the given points P₁ : m₁ = 6, P₁(1, −2) m₂ = 5, P₂(3, 4) m3 = 1, P3(−3,−7) m₁ = 4, P₁(6,−1) Find the moments Mx, My, and the x and y-coordinates of
the center of mass of the system.
Mx
My
=
=
I-
▶
x-coordinate of the center of mass: x =
y-coordinate of the center of mass: y =
B
▶
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- F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Settingarrow_forwardA point P is located at (0 0 100) in a body coordinate frame. If the rigid body rotates 60deg about the global X-axis and the origin of the body translates to (X, Y, Z)=(500, 0 600), find the final position (X2, Y2, Z2) in the Global frame by using 4X4 matrix.arrow_forwardDon't skip the steps/explanationarrow_forward
- The resultant forces in two * :directions are P=300N K=200N 30 Ry =RX=Zero O RX=312.12N and RY= 38.92N O RX= 38.92N and RY= 312.12Narrow_forwardThe traffic light shown below is supported by a system of cables. Points A and B are in a vertical plane which is parallel to the x-z plane. Point C is in the y-z plane. B h Z X The traffic light has a mass of 75 kg The distances are: a = 4 m, b = 6 m, c = 9 m, h = 6 m To answer the next set of questions you will determine the following: a. Position vectors for OA, OB, OC b. Unit vectors for OA, OB, OC c. Overall equilibrium equation d. Equilibrium equations in each of the x,y and z directions e. The tensions in the cables OA, OB and OC The traffic light has a mass of 75 kg. The distances are: a = 4m, b = 6 m, c = 9m, h = 6 m. Determine the position vector for OB. The position vector FOB can be written in the form: TOB = TOB₂i+TOB] + Tobak You will have to input each of these three components separately below. Given: • • • The x component of the position vector, TOA = 4 m. They component of the position vector,TOA = -9 m. is the z component of the position vector,TOA = 6 m. 1. What is…arrow_forward
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