The following limit results in when you first try to plug in the limit value. Complete the steps below to show that the limit exists through the factor and cancel method. x² - 2x - 3 lim x3 2x2-3x - 9 STEP 1: If possible, factor the numerator into linear factors: STEP 2: If possible, factor the denominator into linear factors: STEP 3: Simplify the function by cancelling any common factors between the numerator and denominator: lim x-3 STEP 4: Now evaluate the limit and answer as an integer or a reduced fraction. x² - 2x - 3 lim x3 2x2-3x - 9

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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0
The following limit results in
when you first try to plug in the limit value.
0
Complete the steps below to show that the limit exists through the factor and cancel method.
x² - 2x - 3
lim
x3 2x2-3x - 9
STEP 1: If possible, factor the numerator into linear factors:
STEP 2: If possible, factor the denominator into linear factors:
STEP 3: Simplify the function by cancelling any common factors between the numerator and
denominator:
lim
x-3
STEP 4: Now evaluate the limit and answer as an integer or a reduced fraction.
x² 2x - 3
lim
x3 2x2-3x - 9
Transcribed Image Text:0 The following limit results in when you first try to plug in the limit value. 0 Complete the steps below to show that the limit exists through the factor and cancel method. x² - 2x - 3 lim x3 2x2-3x - 9 STEP 1: If possible, factor the numerator into linear factors: STEP 2: If possible, factor the denominator into linear factors: STEP 3: Simplify the function by cancelling any common factors between the numerator and denominator: lim x-3 STEP 4: Now evaluate the limit and answer as an integer or a reduced fraction. x² 2x - 3 lim x3 2x2-3x - 9
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