(1) Run the Apriori algorithm (mentally, not through any computer program) and compute Ci (candidate itemset) and L; (frequent itemset) for each iteration i. In computing C₁, please apply self-joining and pruning. Compare your answers with the following and select all the correct ones. C₁ = {m, o, n, k, e, y, d, a, u, c, i} and L₁ = {m, o, k, e} C₁ = {m, o, n, k, e, y,, d, a, u, c, i} and L₁ = {m, o, k, e, y} C₁ = {m, o, n, k, e, y, d, a, u, c, i} and L₁ = {m, n, o, k, e, y} C2 = {mo, mk, me, my, ok, oe, oy, ke, ky, ey} and L2 = {mk, ok, oe, ke} C₂ = {mo, mk, me, my, ok, oe, oy, ke, ky, ey} and L2 = {mk, ok, oe, ke, ky} C₂ = {mo, mk, me, my, ok, oe, oy, ke, ky, ey} and L2 = {mk, mn, ok, oe, ke, ky} C3 = {oke} and L3 = {oke} C3 = {oke, key} and L3 = {oke, key} C3 = {oke, key} and L3 = {oke} The following database has 5 transactions. Let min_sup = 60% and min_conf = 80%. TID Items_bought T100 {m, o, n, k, e, y} T200 {d, o, n, k, e, y} T300 {m, a, k, e} T400 {m, u, c, k, y} T500 {c, o, k, i, e}
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- A database has four transactions. Let min sup = 60% and min conf = 80%.cust ID TID items bought (in the form of brand-item category)01 T100 {King’s-Crab, Sunset-Milk, Dairyland-Cheese, Best-Bread}02 T200 {Best-Cheese, Dairyland-Milk, Goldenfarm-Apple, Tasty-Pie, Wonder-Bread}01 T300 {Westcoast-Apple, Dairyland-Milk, Wonder-Bread, Tasty-Pie}03 T400 {Wonder-Bread, Sunset-Milk, Dairyland-Cheese}(a) At the granularity of item category (e.g., itemi could be “Milk”), for the ruletemplate,∀X ∈ transaction, buys(X,item1) ∧ buys(X,item2) ⇒ buys(X,item3) [s,c],list the frequent k-itemset for the largest k, and all the strong association rules(with their support s and confidence c) containing the frequent k-itemset for thelargest k.(b) At the granularity of brand-item category (e.g., itemi could be “Sunset-Milk”),for the rule template,∀X ∈ customer, buys(X,item1) ∧ buys(X,item2) ⇒ buys(X,item3),list the frequent k-itemset for the largest k (but do not print any rules).A manager has a list of items that have been sorted according to an item ID. Some of them are duplicates. She wants to add a code to the database that assigns a 1 to the item if it is unique, and if there are duplicates, assigns the number of the duplicate. An example is shown below. The first two items are unique, so the repeat code is 1. However, Item ID 37695 is listed six times, so the codes are assigned from 1 to 6, and so on. Explain how to assign the correct code using an IF statement Item ID Repeat Code35080 135222 137695 137695 237695 337695 437695 537695 637712 137722 137757 137757 2 In cell B2 enter 1, and then type a formula into cell B3, followed by dragging the formula down column B until it aligns with the last row in the Item ID column. Which of the following is the correct formula to type into cell B3?Write Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.
- The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENANCE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, create a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team.Write Mysql code for: The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.In this database we have users that can be two types students or instructors. They have groups and memberships. Any user can post and the post type can be video, photo or text. Here is the table structure: CREATE TABLE USER_ ( USER_ID INT NOT NULL AUTO_INCREMENT, CREATE_DATE DATE NOT NULL, PROF_DESC VARCHAR (100), PROF_PIC VARCHAR(40), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (USER_ID) ); CREATE TABLE USER_INFO( USER_ID INT NOT NULL, SU_EMAIL CHAR(18), USER_FNAME VARCHAR(15), USER_LNAME VARCHAR (15), USER_DOB DATE, USER_GENDER CHAR(1), PRIMARY KEY (USER_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE STUDENT ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, YEAR_ VARCHAR (10), MAJOR VARCHAR (20), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (SU_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE INSTRUCTOR ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, DEPARTMENT VARCHAR (40), INSTR_TYPE VARCHAR (40),…
- Below is a schema for an HR database:employee(empid, fname, lname, managerid, departmentid, employee_rank)It's an employee table, which has employee id, first name, last name, manager id (which is an employee id), department id, and employee_rank, such as VP, CEO, SVP, etc.Using SQL, answer this question (write a SQL query that answers this question) [tip: use a recursive query]. 11. For employee 42, find the path-of-managers directly to the CEO?In this database we have users that can be two types students or instructors. They have groups and memberships. Any user can post and the post type can be video, photo or text. Here is the table structure: CREATE TABLE USER_ ( USER_ID INT NOT NULL AUTO_INCREMENT, CREATE_DATE DATE NOT NULL, PROF_DESC VARCHAR (100), PROF_PIC VARCHAR(40), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (USER_ID) ); CREATE TABLE USER_INFO( USER_ID INT NOT NULL, SU_EMAIL CHAR(18), USER_FNAME VARCHAR(15), USER_LNAME VARCHAR (15), USER_DOB DATE, USER_GENDER CHAR(1), PRIMARY KEY (USER_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE STUDENT ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, YEAR_ VARCHAR (10), MAJOR VARCHAR (20), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (SU_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE INSTRUCTOR ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, DEPARTMENT VARCHAR (40), INSTR_TYPE VARCHAR (40),…The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results.
- The following three tables make up a simple reservation system for a small campground. The database should allow for a camper to make multiple reservations for future dates and for a camping spot to have several reservations for upcoming visits. Table: Camper CAMPER_NUMBER 1000 1001 1002 1003 CAMPER_LAST_NAME Jones Schmidt Williams Cooper CAMPER_FIRST_NAME Jamie Pat Clifford Amanda CAMPER_ADDRESS 1278 Essex Pl 4954 Spangled Way 956 Segull Lane P. O. Box 998877 CAMPER_CITY Birmingham El Paso Portland Portsmouth CAMPER_STATE AL TX ME OH CAMPER_ZIP_CODE 45251 79919 4108 45662 CAMPER_DRIVERS_LICENSE JJ998743-98 87632434 WIL885123 765A876B897 CAMPER_EMAIL jjones@somewhere.com patwonderfu34l@nowhere.net williams98342@foomail.com coopera@nowhere.net Table: Spot SPOT_NUMBER 101 102 103 104 SPOT_NAME The Pines The Glade Teardrop Spot Tent In Trees SPOT_LENGTH 55 50 20 0 SPOT_PULLTHRU 1 0 0 0 SPOT_ELECTRIC_AMPS 50 50 20 0…Use Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.1) Assume the EMPLOYEE table has the following rowsID DEPT SALARY NAME100 SALES 40000 Smith101 RD 38000 Terry102 HR 60000 David103 SALES 58000 Ellie104 RD 70000 Judya) Provide the complete PL/SQL code to implement a Virtual Private Database suchthat an employee could only view the records for employees in the samedepartment while masking coworkers’ salary with NULL.b) Based on the Virtual Private Database you implemented in step a), would anemployee be able to insert, update or delete a record for another employee whoworks in another department? If yes, what might be the potential security risk andhow would you fix the problem by setting up the VPD appropriately?