ID=3.3333 The following data given are collected from the experimental measurement on theelectrical circuit with the current as input variable and voltage as output variable:(b)6 7.2451a 57la1.22.43.64.8v(i)21a9la18la27la38laCompare FOUR(4) suitable methods to approximate v'(6) in 4 decimal places inwhich the exact solution of v'(6) is 8.3878.(c)A point P is moving along the curve whose equation is f(x) = lae2x+3 . By usingsecond derivative for 3-point central and 5-point difference formula with h = 0.05 ,calculate how far P is moving when x = 1.25.

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Answered: The following data given are collected…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 91E

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3) Let's examine the levels of levels of sodium in the blood. 20 people yield the following results (in mEq/L): ̄y = 136.95 s = 2.544 (a) Test H0: μ = 140 using α = 0.001 (that's not a typo).(b) Figure out the p-value. To do this, take the t value that you calculated in (a) and use R: pt(absolute-value-of-your-t*, df, lower.tail = FALSE)*2 Since it's a two-sided test, you need to multiply by 2 at the end. We'll talk more about this in lecture when we do one sided tests; for now just realize that without the “*2” at the end R gives you a one sided p-value. For example, if your t* = 4.65 and you have 67 degrees of freedom you would do: pt(4.65,67,lower.tail = FALSE)*2 and you would get back 1.609352e-05
3) Let's examine the levels of levels of sodium in the blood. 20 people yield the following results (in mEq/L): ̄y = 136.95 s = 2.544 (a) Test H0: μ = 140 using α = 0.001 (that's not a typo).(b) Figure out the p-value. To do this, take the t value that you calculated in (a) and use R: pt(absolute-value-of-your-t*, df, lower.tail = FALSE)*2 Since it's a two sided test, you need to multiply by 2 at the end. We'll talk more about this in lecture when we do one sided tests; for now just realize that without the “*2” at the end R gives you a one sided p-value. For example, if your t* = 4.65 and you have 67 degrees of freedom you would do: pt(4.65,67,lower.tail = FALSE)*2 and you would get back 1.609352e-05 (c) Is the p-value smaller than α?(d) Why is this (c) important (see also part (a))? It is essential that you understand question (c)! (e) What is the smallest value of α for which you would reject the H0? Hint: this will not be a “standard” value of α. The correct answer here is a value…
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