The following data are from an experiment on carnations. The explanatory variable is the amount of inorganicbromine (micrograms per milliliter) in a plot of standard size. The response variable is the average number offlowers per carnation plant for the 30 plants grown in the plot. Which of the following statements is true?BromineAverage No.3 43.2 2.963.7C.72.28 10 12 15 161.8 2.3 1.7 0.8 0.3Select one:a. The value of r is positive and the scatterplot shows that the average number of flowers per carnationincreases as the amount of bromine increases.b. The value of r is negative and the scatterplot shows that the average number of flowers per carnationdecreases as the amount of bromine increases.The value of r is positive and the scatterplot shows that the average number of flowers per carnationdecreases as the amount of bromine increases.d. The value of r is negative and the scatterplot shows that the average number of flowers per carnationincreases as the amount of bromine increases.

Let X: the amount of bromine and Y: the average number of flowers per carnationTotal observations,

Answered: The following data are from an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let x represent the hemoglobin count (HC) in grams per 100 milliliters of whole blood. The distribution for HC is approximately normal with μ = 14 for healthy adult women. Suppose that a female patient has taken 12 laboratory blood samples in the last year. The HC data sent to her doctor is listed below. We would like to know if the data indicates this patient has significantly high HC compared to the population. 14,19,16,14,19,19,14,21,17,17,14,17 Give the p-value and interpret the results. a) p = 0.0012; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. b) p = 0.0012; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. c) p = 0.0023; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. d) p = .1053; Based on 5% significance level, I will fail to reject the null hypothesis and…
Still need D , E and F
Let x represent the hemoglobin count (HC) in grams per 100 milliliters of whole blood. The distribution for HC is approximately normal with μ = 14 for healthy adult women. Suppose that a female patient has taken 12 laboratory blood samples in the last year. The HC data sent to her doctor is listed below. We would like to know if the data indicates this patient has significantly high HC compared to the population. 22,17,20,17,17,14,16,21,15,21,15,22 Give the p-value and interpret the results. a) p = .1053; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. b) p = .0562; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. c) p = 0.0003; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. d) p = 0.0003; Based on 5% significance level, I will reject the…
Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and ? = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is ? = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. Level of significance = .10 Null and alternate hypotheses. - H0: ? = 4.3 g; H1: ? < 4.3 g; left-tailed Sampling Distribution - The standard normal, since we assume that x has a normal distribution with known ? Compute the z value of the sample test…
Listed below are the measured radiation emissions (in W/kg) corresponding to cell phones: A, B, C, D, E, F, G, H, I, J, and K respectively. The media often present reports about the dangers of cell phone radiation as a cause of cancer. Cell phone radiation must be 1.6 W/kg or less. Find the a. mean, b. median, c. midrange, and d. mode for the data. Also complete part e. 0.32 1.49 1.41 0.27 1.08 0.77 0.55 0.22 1.17 1.28 1.06 a. Find the mean. The mean is (Round to three decimal places as needed.) ... n
Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and σ = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is μ = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. (a) What is the level of significance? (Enter a number.) State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: μ = 4.3 g; H1: μ > 4.3 g; right-tailed H0: μ < 4.3 g; H1: μ = 4.3 g; left-tailed…
The authors of a paper were interested in how the distance a deer mouse will travel for food is related to the distance from the food to the nearest pile of debris. Distances were measured in meters. The data and computer output are given below. Distance from Debris Distance Traveled 6.94 0.00 5.23 6.13 5.21 11.29 7.10 14.35 8.16 12.03 5.50 22.72 9.19 20.11 9.05 26.16 9.36 30.65 Simple Linear Regression Results: Dependent Variable: Traveled Independent Variable: Debris Sample size: 9 R (correlation coefficient) = 0.5657 R-sq = 0.32002088 Estimate of error standard deviation 8.670711 Parameter estimates: Parameter Estimate Std. Err. Alternative DF T-Stat P-Value Intercept -7.6854587 13.332196 ≠ 0 7 -0.5764586 0.5824 Slope 3.2340908 1.7818117 ≠ 0 7 1.8150575 0.1124 a)What is the least squares regression line for the output given above? b) what is the predicted traveled distance given the distance from debris is 6.5 meters?
Use the t3 I calculator.
Two universities give samples of students the same exam. School A records the follwoing sample statistics: ā1=73, 8,=5.5, ni =80. School B records the follwoing sample statistics: z=69, ,=4.4, n2 =90. We wish to build a 95 % cofidence interval to estimate the difference in means between these schools. Define your variable: O Let p be the proprotion School A students that were higher than School B. Let u the mean test score that School A was higher than School B. Let u be the mean test score. O Let u be the mean test score at School A. Create and interpret a 95% Confidence Interval. Round your answers to one decimal place. Select an answer and Select an answer What is the margin of error? Round your answer to one decimal place. Do these results suggest that School A might have higher means on this test? ? Do these results PROVE that School A might have higher means on this test? The campus president at School A made the following statement. "Our students score an average of 5 points…
Please answer b and c
A group of 100 people, who lived at varying distances (in kilometers) from an island nuclear power station, were asked if they thought a full evacuation of the area was required, when it went critical. The researches wanted to know if the opinion to evacuate or not depended on how far from the reactor people lived. Partial results of the questionnaire are shown in the table below. 0-3 km distance 3 -6 km distance 6 -9 km distance 9- 12 km distance Totals Evacuation needed X X X 51 Evacuation not X X XX needed Totals 28 28 23 XX XX You are doing a Chi Square test for independence. What is the expected value of the number of people living within a radius of 0-3 km who would say that evacuation was needed? XX denotes row/column totals. Give your answer to 2 decimal places.

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