The focal length of a diverging lens is negative. If f = −17 cm for a particular diverging lens, where will the image be formed of an object located 64 cm to the left of the lens on the optical axis? _______________cm to the left of the lens What is the magnification of the image?

Please use lensmaker’s equation to design a double converging lens with 4 cm focal length.R1 = 10meters, refraction index of glass is 1.5. Calculate R2

An object 4 cm tall is placed in front of the converging lens has a focal length of 10 cm. For each situation below, locate and describe the image (type, orientation, size, and location) using a ray diagramand the lens equations if the object is placed 40 cm from the lens. 30 cm from the lens. 20 cm from the lens 15 cm from the lens 5 cm from the lens

A converging lens has a focal length of 4.0 cm A 1.5 cm object is placed 6.0 cm to the left of the lens (as shown in the diagram below) Part A The distance of the image will be ανα ΑΣφ d; = cm Submit Request Answer Part B The height of the image will be Πνη ΑΣφ ? h4 = cm Submit Request Answer Part C The image is and O real, upright O real, inverted O virtual, inverted O virtual, upright