The floor of a light storage warehouse is made of 6-in.-thick cinder concrete. The floor is a slab having a length of 17 ft and width of 15 ft. Part A Determine the resultant force caused by the dead load. Express your answer using three significant figures. DL= Submit Part B LL= 195| ΑΣΦ | 11 Submit Request Answer Determine the resultant force caused by the live load. Express your answer using three significant figures. 15] ΑΣΦ vec Request Answer vec ? k k

The floor of a light storage warehouse is made of 6-in.-thick cinder concrete. The floor is a slab having a length of 17 ft and width of 15 ft. Part A Determine the resultant force caused by the dead load. Express your answer using three significant figures. DL= Submit Part B LL= 195| ΑΣΦ | 11 Submit Request Answer Determine the resultant force caused by the live load. Express your answer using three significant figures. 15] ΑΣΦ vec Request Answer vec ? k k

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Provide correct answer Thanks for the help Determine maximum principal stress
2) The flooring system shown is composed of slab panels measuring 20 X 25 ft in plan, supported by shallow column-line beams, as shown in the figure. The slab is pre-cast and resting on the beams. The panels carry a service live load of 144 psf in addition to the self-weight of the floor. a) Calculate the factored load on beam CD as per the tributary area shown. Assume a slab thickness of 7 in and the density of the concrete used to be 150 pcf. Use the load combinations from the ASCE 7-10 load combinations for Strength Design (2.3.2). b) Sketch the bending moment diagram (BMD) for the beam using the factored load calculated in step (a). c) Calculate Mu for the trapezoidal load distribution. d) Design a reinforced concrete beam using a rectangular section to carry the Mu calculated in step (c). You can use design guides, but show clear steps. Use concrete with fc'=4000 psi and steel with fy = 60000 psi.
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Provided is the question along with some notes taken in the lecture, i am not sure if i am correst so if you could do some workings out for me that would be great , thank you.
Question from Subject Mechanics of Deformable Solids.
A TIMBER BLOCK “B x B” mm SQUARE IS REINFORCED ON OPPOSITE SIDES BY A “B” mm AND ‘t’ mm THICK STEEL PLATES. DETERMINE THE THICKNESS ‘t’ SO THAT THE ASSEMBLY WILL SUPPORT AN AXIAL LOAD OF 1000 KN WITHOUT EXCEEDING A MAXIMUM TIMBER STRESS OF 12 MPa OR A MAXIMUM STRESS IN STEEL OF 350 MPa. MODULUS OF ELASTICITY OF STEEL AND TIMBER ARE 210 GPa & 7 GPa RESPECTIVELY.
Current Attempt in Progress A simply supported timber beam with length L = 3 m carries a uniformly distributed load w = 11 kN/m. Determine the magnitude of the maximum compression bending stress that occurs in the beam at any location within the 3-m span length. 300 mm L 100 mm O 7.47 MPa O 5.18 MPa O 9.74 MPa O 8.25 MPa O 5.92 MPa Save for Later Attempts: 0 of 1 used Submit Answer
Situation 1| Consider the figure 1 below. 3- 25mmØ bolts are used to fasten a plate to a steel beam. 1) Determine the average shearing stress caused in each bolt by the 30kN loads 2) Determine the value of additional load P that must be applied so that each bolt will not exceed the maximum shearing stress of 60MPA. 30 kN 150. 300 200 30 kN P.
Calculate the resultant force acting on the curved surface BC. Assume section is 4m perpendicular to the paper. List the given, required, graph and box the final answer
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Determine the losses in the post-tensioned concrete beam as shown below. 560 mm Given: POST-TENSIONED BEAM with A PARABOLIC TENDON PROFILE Span Length = 20 m fi = 1200 N/mm² A, = 2850 mm² Ac 4.23x105 mm² 1=9.36x10¹0 mm e-560 mm (@midspan, from N.A.) fc= 40 N/mm² Es = 210,000 N/mm² μ = 0.19 K = 0.0005 (per meter) Anchorage slip = 5 mm (jacked at left-end only). (make sure to draw the force variation diagram for anchorage slip) V/S= 6 RH = 70 Dead Load 9.97 kN/m fpy = 1714 N/mm² Bridge Width III
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