The float level h of a hydrometer is a measure of the specific gravity of the liquid. For stem diameter D and total weight W, if h= 0 represents SG=1.0, what is the formula for has a function of W, D, SG, and yo for water? D SG=1.0 Fluid, SG > 1

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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**Understanding Hydrometer Measurements and the Float Level**

A hydrometer is an instrument used to measure the specific gravity (SG) of a liquid, which is the ratio of the density of the liquid to the density of water. The hydrometer consists of a calibrated stem and a weighted bulb that allows it to float. 

**Problem Statement:**
Given:
- The float level \( h \) of the hydrometer is a measure of the specific gravity of the liquid.
- For stem diameter \( D \) and total weight \( W \),
- If \( h = 0 \) represents SG = 1.0,

**Question:**
What is the formula for \( h \) as a function of \( W, D, \) SG, and \( \gamma_0 \) for water?

**Diagram Explanation:**
The diagram provided showcases a hydrometer floating in a liquid of specific gravity greater than 1 (SG > 1). 

- The vertical component \( h \) is the floating height measured from the fluid's surface to a marked point on the stem.
- The diameter of the stem where the measurement takes place is \( D \).
- The label SG = 1.0 corresponds to the point where \( h = 0 \).
- The total weight of the hydrometer is \( W \).
- The fluid in which the hydrometer is immersed has a specific gravity greater than one compared to water.

**Visual Guide:**
- The hydrometer is partially submerged, with its weighted bulb below and the stem extending upwards.
- The diagram indicates fluid with specific gravity greater than one around the hydrometer's bulb.
- The stem diameter \( D \) is clearly marked near the top of the fluid level.

This setup helps learners understand how changes in specific gravity of the fluid affect the float level \( h \) of the hydrometer. The relationship between the hydrometer’s weight, the diameter of its stem, and the specific gravity of the fluid are crucial in determining the formula for \( h \).
Transcribed Image Text:**Understanding Hydrometer Measurements and the Float Level** A hydrometer is an instrument used to measure the specific gravity (SG) of a liquid, which is the ratio of the density of the liquid to the density of water. The hydrometer consists of a calibrated stem and a weighted bulb that allows it to float. **Problem Statement:** Given: - The float level \( h \) of the hydrometer is a measure of the specific gravity of the liquid. - For stem diameter \( D \) and total weight \( W \), - If \( h = 0 \) represents SG = 1.0, **Question:** What is the formula for \( h \) as a function of \( W, D, \) SG, and \( \gamma_0 \) for water? **Diagram Explanation:** The diagram provided showcases a hydrometer floating in a liquid of specific gravity greater than 1 (SG > 1). - The vertical component \( h \) is the floating height measured from the fluid's surface to a marked point on the stem. - The diameter of the stem where the measurement takes place is \( D \). - The label SG = 1.0 corresponds to the point where \( h = 0 \). - The total weight of the hydrometer is \( W \). - The fluid in which the hydrometer is immersed has a specific gravity greater than one compared to water. **Visual Guide:** - The hydrometer is partially submerged, with its weighted bulb below and the stem extending upwards. - The diagram indicates fluid with specific gravity greater than one around the hydrometer's bulb. - The stem diameter \( D \) is clearly marked near the top of the fluid level. This setup helps learners understand how changes in specific gravity of the fluid affect the float level \( h \) of the hydrometer. The relationship between the hydrometer’s weight, the diameter of its stem, and the specific gravity of the fluid are crucial in determining the formula for \( h \).
### Multiple Choice Questions

#### Question:
Calculate the value of \( h \) using the correct formula. 

Please select the correct formula for \( h \) from the options below:

1. 
\[ h = \frac{W(SG - 1)}{SG \gamma_0 \left(\frac{\pi}{4}D^2 \right)} \]

2. 
\[ h = \frac{(SG + 1)}{W \cdot SG \gamma_0 \left(\frac{\pi}{4}D^2 \right)} \]

3. 
\[ h = \frac{W \left(\frac{\pi}{4} D^2 \right)}{(SG - 1) \gamma_0} \]

4. 
\[ h = \frac{W \left(\frac{\pi}{4} D^2 \right)}{(SG + 1) \gamma_0} \]

### Explanation of Diagram:
The image contains four options for calculating the value of \( h \). Each option includes a formula that involves the following variables:

- \( W \) : Weight
- \( SG \) : Specific Gravity
- \( \gamma_0 \) : Unit Weight of Water
- \( D \) : Diameter
- \(\pi\) : Pi (approximately 3.14159)

Each formula uses these variables with different operations and combinations to solve for \( h \). 

Please carefully review the options and choose the one that correctly calculates the value of \( h \).
Transcribed Image Text:### Multiple Choice Questions #### Question: Calculate the value of \( h \) using the correct formula. Please select the correct formula for \( h \) from the options below: 1. \[ h = \frac{W(SG - 1)}{SG \gamma_0 \left(\frac{\pi}{4}D^2 \right)} \] 2. \[ h = \frac{(SG + 1)}{W \cdot SG \gamma_0 \left(\frac{\pi}{4}D^2 \right)} \] 3. \[ h = \frac{W \left(\frac{\pi}{4} D^2 \right)}{(SG - 1) \gamma_0} \] 4. \[ h = \frac{W \left(\frac{\pi}{4} D^2 \right)}{(SG + 1) \gamma_0} \] ### Explanation of Diagram: The image contains four options for calculating the value of \( h \). Each option includes a formula that involves the following variables: - \( W \) : Weight - \( SG \) : Specific Gravity - \( \gamma_0 \) : Unit Weight of Water - \( D \) : Diameter - \(\pi\) : Pi (approximately 3.14159) Each formula uses these variables with different operations and combinations to solve for \( h \). Please carefully review the options and choose the one that correctly calculates the value of \( h \).
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