The first four moments of a distribution about the value '4' of the various are – 1-5, 17 – 30 and 108. Find the moments about mean, B, and B,.
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- from year s of teaching ,a statsitics profeessor knoes that Amy , her student 's test scre will be a randonm variable with mean = 75 and variance = 25. what can be the lowest estimate on probability that Amy will socre between 65 and 85.The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EUToday, the waves are crashing onto the beach every 5 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 2 seconds after the person arrives is P(x = 2) = The probability that the wave will crash onto the beach between 0.4 and 2.9 seconds after the person arrives is P(0.4 < x < 2.9) = The probability that it will take longer than 1.5 seconds for the wave to crash onto the beach after the person arrives is P(x > 1.5) = Suppose that the person has already been standing at the shoreline for 1.3 seconds without a wave crashing in. Find the probability that it will take between 2.7 and 4.8 seconds for the wave to crash onto the shoreline. 27% of the time a person will wait at least how long before the wave crashes in?…
- For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years. POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…Suppose X ~ N(3, 1.2). What value of x is two standard deviations to the right of the mean?The chart to the right shows that a professor's grading distribution is bell shaped, or normally shaped. The mean of the distribution is 74 and the standard deviation is 9. Using a Continuous Variable Normal Bell Distribution Model, calculate the minimum test score needed to score in the top 5% of the class. Complete your work in the worksheet by listing the formula inputs, labels for the formula inputs and make your calculations with formulas. This test problem is similar to what you studied in video # 32, 33 and 34 and homework problems # 17, 21 and 23. Relative Frequency Frequency Professor looks at all test score for a particular test (this is population data), and observes: 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0 Mean = 74 Median = 74 Mode = 73 SD=9 0 0 0 up to 10 up 10 to 20 0 20 up to 30 0 30 up to 40 2 40 up to 50 29 50 up to 60 X = Score 112 60 up to 70 225 70 up to 80 111 80 up to 90 21 2 90 up 100 up to 100 to 110
- Florida State University has 14 statistics classes scheduled for its Summer 2013 term. One class has space available for 30 students, eight classes have space for 60 students, one class has space for 70 students, and four classes have space for 100 students. Find the mean of X (Round to 2 decimal places)Find the variance of [6 ,7 ,10 ,11 ,12 ,13 ,16 ,18 ,25].Round off your final answer into two decimal places.Suppose X ~ N(6, 2). What value of x is two standard deviations to the right of the mean?
- A mathematics professor one to determine whether there is a different in the final average just between the past two semester (semester 1 and semester 2) of his business is statistics classes. For a random sample of 16 students from semester 1, the mean of the final averages was 75 with a standard deviation of 4. For a random sample of 9 students from semester 2, the mean was 73 with a standard deviation of 6. Choose the correct answerfor data set of the pulse rates for a sample of adult females the lowest pulse rate is 36 bpm the mean of the list of pulse rate is X bar equals 72 bpm and their standard deviation is 12.9 bpm. what is the difference between the pulse rate of 36 bpm and the meatballs rid of the females how many celebrations is that the difference found in part a convert the pulse rate of 36 bpm to a z score if we consider pulse rates that convert to a Z score between -2 and 2 to be neither significantly lower significantly high is the pulse rate of 36bpm significantA driver has pumped 13 gallons of gas to his track. On average day that driver has to spend 2 gallons of gas with the deviation 1 gallons. Calculate the probability that these 13 gallons of gas will be enough for next 6 days of driving that track.
