The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.26 mA out of the page, and is at distance d₁ = 2.74 cm from a surface. Wire 2, which is parallel to wire 1 and also long, is at horizontal distance d₂ = 5.02 cm from wire 1 and carries a current of 7.05 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1? 1
The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.26 mA out of the page, and is at distance d₁ = 2.74 cm from a surface. Wire 2, which is parallel to wire 1 and also long, is at horizontal distance d₂ = 5.02 cm from wire 1 and carries a current of 7.05 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1? 1
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Transcribed Image Text:The
figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.26 mA out of the page, and is at distance d₁
= 2.74 cm from a surface. Wire 2, which is parallel to wire 1 and also long, is at horizontal distance d₂ = 5.02 cm from wire 1 and carries
a current of 7.05 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1?
1
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VIEWStep 2: Calculate the magnitude of the magnetic field induced at the position of wire 2 due to wire 1.
VIEWStep 3: Determine the magnetic field vector due to wire 1 at the position of wire 2.
VIEWStep 4: Calculate the x-component of the magnetic force per unit length on wire 2 due to wire 1:
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