The figure shows three vectors. Vector A has a length of 36.0. vector B has a length of 66.0, and vector C has a length of 23.0. Macmillan Learning Solve the given equations. A.B= B. (A+C) = At what angles above and below the horizontal line could vector A be at so that A B0? O90 above or 90° below 20 above or 160 below O110 above or 70" below 90 above or 70" below 70° 70° 20⁰

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Chapter1: Units, Trigonometry. And Vectors
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Macmillan Learning
The figure shows three vectors. Vector A has a length of 36.0.
vector has a length of 66.0, and vector C has a length of
23.0.
Solve the given equations.
A.B=
B. (λ + C) =
At what angles above and below the horizontal line
could vector A be at so that AB=0?
90 above or 90° below
20 above or 160" below.
110 above or 70" below
90 above or 70" below
70°
70°
A
20°
Transcribed Image Text:Macmillan Learning The figure shows three vectors. Vector A has a length of 36.0. vector has a length of 66.0, and vector C has a length of 23.0. Solve the given equations. A.B= B. (λ + C) = At what angles above and below the horizontal line could vector A be at so that AB=0? 90 above or 90° below 20 above or 160" below. 110 above or 70" below 90 above or 70" below 70° 70° A 20°
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