The figure shows a parallel-plate capacitor of plate area A = 10.9 cm² and plate separation 2d= 7.25 mm. The left half of the gap is filled with material of dielectric constant K₁ = 21.6; the top of the right half is filled with material of dielectric constant K2 = 46.9; the bottom of the right half is filled with material of dielectric constant K3 = 57.6. What is the capacitance? Number i Units ↑ 2d A/2- K1 -A/2 K₂ K3

3. The Figure below shows a parallel-plate capacitor of plate area A= 10.5 cm² and plate separation 2d=7.12 mm. The left half of the gap is filled with material of dielectric constant K₁= 21.0; the top of the right half is filled with material of dielectric constant K₂ = 42.0; the bottom of the right half is filled with material of dielectric constant K3 = 58.0. What is the capacitance? 2d K₁

An air-filled parallel-plate capacitor has a capacitance of 2 pF. The plate separation is then halved and a wax dielectric is inserted, completely filling the space between the plates. As a result, the capacitance becomes 8 pF. The dielectric constant of the wax is:

A parallel plate capacitor with air between its plates is charged to 86.6 V and then disconnected from the battery. When an unknown dielectric material is placed between the plates, the voltage across the capacitor drops to 21.519 V. What is the dielectric constant of the unknown material? Assume that the material fills the space between the plates completely. Round your answer to 2 decimal places.

A 37 uF capacitor is being charged by a voltage source and the energy stored is equal to 249.48 uJ. While the capacitor is still connected to the voltage source, a dielectric material is inserted between the plates. As a result, the energy stored increases by 347.73 uJ. The dielectric constant of this material is equal to

An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = C

Note: The value of a=0, b=5 and C=7.